All categories

4 years ago

1 tree makes approximately 230 newspapers. Estimate (by rounding each number to 1 S.F.) how many newspapers 56 trees will make.

Mathematics

2 answers:

g100num [7]4 years ago

6 0

Answer:

56 trees will make 10000 newspapers.

Step-by-step explanation:

Given:

One tree makes approximately 230 newspapers.

Now, for estimating how many newspapers will be made with 56 trees.

By multiplying $56$ trees with $230$ newspapers we get,

$56\times230=12880$ .

And, rounding $12880$ to one significant number (1 S.F.) is $10000$ .

Therefore, 56 trees will make 10000 newspapers.

Katena32 [7]4 years ago

3 0

Answer: The answer is 12,880 newspapers

Step-by-step explanation:

Step one : given that

1 tree produces 230 news papers

56 tree will produce X newspapers

Step: cross multiplying to get the value of x

X= 56*230

X=12,880

You might be interested in

4x + 6 - x = 7 + 2 x

rodikova [14]

Answer:

x = 1

Step-by-step explanation:

4x + 6 - x = 7 + 2x

3x + 6 = 7 + 2x

3x - 2x = 7 - 6

x = 1

8 0

3 years ago

Read 2 more answers

What is the distance from X to Y?

densk [106]

Answer:

Step-by-step explanation:

distance formula

$\sqrt{((x2-x1)^2 + (y2-y1)^2)}$

$\sqrt{(9-0)^2 + (-6-6)^2}$

$\sqrt{81 + 144}$

$\sqrt{225}$

7 0

3 years ago

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$