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Reika [66]
3 years ago
11

The square of the sum of a number and 3 is 16. Find the number.(There are two solutions.)

Mathematics
2 answers:
iren2701 [21]3 years ago
5 0
1,-7 hope this helps
mote1985 [20]3 years ago
3 0

Answer:

1 , -7

Step-by-step explanation:

(x+3)² = 16

then

(x+3)² = 4²

then

|x+3| = 4

then

x+3=4 or x+3= -4

then

x=4-3=1  or  x= -4-3= -7

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What number added to 66 is 167
denis-greek [22]

Answer:

101

Step-by-step explanation:

To figure this out, you would do 167 - 66 = 101

101 + 66 = 167

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2 years ago
Four friends purchase a pineapple for $2.89 and 18.4 pounds of peaches. The peaches cost $1.75 per pound. The friends share the
umka21 [38]

Answer: $3.00

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=1%20%5Cdiv%20%20%5Cfrac%7B9%7D%7B5%7D%20" id="TexFormula1" title="1 \div \frac{9}{5} " alt="1
jasenka [17]
The answer to your question is 5/9.
7 0
3 years ago
3x - 5y = 15<br> y = 2x + 4<br><br> What is the solution order pair
laila [671]
It is (-2, -3) im thinking not sure
6 0
3 years ago
Help me please, need this done now.
Nikolay [14]

simplifying \frac{\sqrt{4}}{\sqrt[3]{4}} we get 4^{\frac{1}{6}}

Option B is correct.

Step-by-step explanation:

We need to simplify: \frac{\sqrt{4}}{\sqrt[3]{4}}

Solving:

\frac{\sqrt{4}}{\sqrt[3]{4}}

We know that √ = 1/2 and ∛=1/3

\frac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=4^{\frac{1}{2}-\frac{1}{3}}\\=4^{\frac{3-2}{6}}\\=4^{\frac{1}{6}}

So, simplifying \frac{\sqrt{4}}{\sqrt[3]{4}} we get 4^{\frac{1}{6}}

Option B is correct.

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

  • brainly.com/question/13174260
  • brainly.com/question/13174254
  • brainly.com/question/13174259

#learnwithBrainly

6 0
3 years ago
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