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Anastaziya [24]
3 years ago
12

How many liters are equivalent to 12 US gallons?

Chemistry
2 answers:
telo118 [61]3 years ago
6 0

Answer:

the answer is 6

Explanation: two litter is a gallons so 12 us gallons /2 =6

Ksju [112]3 years ago
3 0

Answer: 45.4249

Explanation:

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Engineers increase output in crop production by combining the strengths of
katrin [286]

Answer:

Cross-pollination

Explanation:

This technique is used to create new varieties, usually with stronger characteristics than the two original varieties. When the pollen of <u>one variety</u> is placed to a <u>different plant's stigma</u>, the resulting seeds create a new variety. This cross-pollination is used in plants of the same species.  

5 0
3 years ago
Using the equations
Anna [14]

Considering the Hess's Law, the enthalpy change for the reaction is 221.8 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: H₂ (g) + F₂ (g) → 2 HF (g)     ∆H° = -79.2 kJ/mol

Equation 2: C (s) + 2 F₂ (g) → CF₄ (g)     ∆H° = 141.3 kJ/mol

Equation 3: 2 C(s) + 2 H₂ (g) → C₂H₄ (g)     ∆H° = -97.6 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

<h3 /><h3>FIRST STEP</h3>

First, to obtain the enthalpy of the desired chemical reaction you need one mole of C₂H₄ (g) on reactant side and it is present in first equation. Since this equation has one mole of C₂H₄ (g) on the product side, it is necessary to locate it on the reactant side (invert it).

When an equation is inverted, the sign of ΔH° also changes.

<h3>SECOND STEP</h3>

Now, you need 2 moles of CF₄ (g) on the product side. The second equation has 1 mole of CF₄ (g) on the product side, so it is necessary to multiply it by 2 to obtain 2 moles of CF₄ (g).

Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 2, the variation of enthalpy also.

<h3>THIRD STEP</h3>

Finally, you need 4 moles of  HF (g) on the product side. The first equation has 2 moles of  HF (g) on the product side, so it is necessary to multiply it by 2 to obtain 4 moles of the compound.

Since the equation is multiply by 2, the variation of enthalpy also is multiplied by 2.

<h3>SUMMARY</h3>

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 H₂ (g) + 2 F₂ (g) → 4 HF (g)     ∆H° = -158.4 kJ/mol

Equation 2: 2 C (s) + 4 F₂ (g) → 2 CF₄ (g)     ∆H° = 282.6 kJ/mol

Equation 3: C₂H₄ (g) → 2 C(s) + 2 H₂ (g)     ∆H° = 97.6 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

C₂H₄ (g) + 6 F₂ (g) → 2 CF₄ (g) + 4 HF (g)     ΔH°= 221.8 kJ/mol

Finally, the enthalpy change for the reaction is 221.8 kJ/mol.

Learn more about molar enthalpy:

  • <u>brainly.com/question/5976752?referrer=searchResults </u>
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7 0
2 years ago
Answer A B C and D please for my chemistry hw
r-ruslan [8.4K]

<u>Answer:</u> The equations are provided below.

<u>Explanation:</u>

Skeleton equations are defined as the equations which simply indicate the molecules that are involved in a chemical reaction. These equations are unbalanced equations.

Balanced equations are defined as the chemical equation in which number of individual atoms on the reactant side must be equal to the number of individual atoms on the product side.

  • For A:

Water decomposes in the direct current to form hydrogen and oxygen.

Skeleton Equation: H_2O(l)\rightarrow H_2(g)+O_2(g)

Balanced Equation: 2H_2O(l)\rightarrow 2H_2(g)+O_2(g)

  • For B:

Mercury (II) oxide decomposes in heat to form mercury, oxygen.

Skeleton Equation: HgO(s)\rightarrow Hg+O_2

Balanced Equation: 2HgO(s)\rightarrow 2Hg+O_2

  • For C:

Calcium carbonate when heated forms calcium oxide and carbon dioxide.

Skeleton Equation: CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

Balanced Equation: CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

  • For D:

Group 2 hydroxides, when heated forms oxide and water vapor.

Skeleton Equation: Ca(OH)_2\rightarrow CaO+H_2O

Balanced Equation: Ca(OH)_2\rightarrow CaO+H_2O

3 0
3 years ago
HELP PLEASE I WILL GIVE YOU BRAINLIEST
Ksivusya [100]
The first and Third graph
6 0
3 years ago
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J.
timofeeve [1]

Complete question:

ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.

Answer:

The magnitude of q for the process 568 J.

Explanation:

Given;

change in internal energy of the gas, ΔU = 475 J

work done by the gas, w = 93 J

heat added to the system, = q

During gas expansion process, heat is added to the gas.

Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.

ΔU = q - w

q = ΔU +  w

q = 475 J  +  93 J

q = 568 J

Therefore, the magnitude of q for the process 568 J.

6 0
3 years ago
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