Ask question

Ask question

All categories

3 years ago

15

How many grams of oxygen are needed to produce 5.40 g of water according to this equation? 2 H2 (g) + O2 (g) ⟶ 2 H2O (l)

1 answer:

garik1379 [7]3 years ago

8 0

Explanation:

https://socratic.org/questions/using-the-equation-2-h2-o2-2-h2o-determine-how-many-grams-of-oxygen-will-be-need

You might be interested in

What are the reactants in photosynthesis?

Sveta_85 [38]

Is this about flowers I kinda remeber but nit really if so it's the polination in flowers I'll find out in the morning

6 0

3 years ago

Read 2 more answers

A student performs a titration analysis for the following balanced reaction: 3 H2SO4 + 2 Al(OH)3 → Al2(SO4)3 + 6 H2O If a 200.0g

adelina 88 [10]

The molar mass of Al(OH)3 = 27+(16+1)*3 = 78 g/mol. Dividing the 200.0 g by the molar mass of 78 g/mol = 2.564 moles. From the balanced equation, 2 moles of Al(OH)3 are equivalent to 1 mole of Al2(SO4)3, so if 2.564 moles of Al(OH3) are used, we divide by 2 to find that 1.282 moles of Al2(SO4)3 are formed. The molar mass of Al2(SO4)3 is 27*2+(32.07+16*4)*3 = 342.21 g/mol, so multiplying this by 1.282 moles gives 438.71 grams of aluminum sulfate produced.

5 0

3 years ago

Argon is contained in a piston-cylinder arrangement at a temperature of 100°C and a pressure of 200 kPa. An isothermal process t

Roman55 [17]

Answer:

a. 1,500 kJ

b. $1.4 x10^4g Ar$

Explanation:

Hello,

In the attached picture you will find the solution for the exercise.

- Take into account that ΔT=0.

Best regards.

8 0

3 years ago

0.73 grams of toluene was reacted with 2.0 grams of potassium permanganate in presence of 7.0 mL of 6 Molar potassium hydroxide

galben [10]

Answer:

The value is $k =66\%$

Explanation:

From the question we are told that

The mass of toluene $m_t =0.73 \ g$

The mass of potassium permanganate is $m =2.0 \ g$

The volume of potassium hydroxide V = 7.0 mL

The concentration of potassium hydroxide C = 6 M

The mass of benzoic acid is $m_b = 0.633 \ g$

Generally the % yield of benzoic acid is mathematically represented as

$k = \frac{m_b}{Z} * 100$

Here Z is the theoretical yield which is mathematically represented as

$Z = \frac{E}{W} * m_t$

Here W is the molecular weight of product (benzoic acid) with value

W = 92.14 \ g

E is the molecular weight of reactant (toluene)with a constant value of

E = 122.12 g

So

$Z = \frac{122.12 }{92.14} * 0.73$

=> $Z = 0.968 \ g$

So

$k = \frac{0.633}{0.968} * 100$

=> $k =66\%$

4 0

3 years ago

What is the hybridization of the central atom in becl2?

Anuta_ua [19.1K]

Its hybridization would be sp because Be only has 2 covalent bonds with Cl

4 0

3 years ago