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Kipish [7]
3 years ago
15

How many grams of oxygen are needed to produce 5.40 g of water according to this equation? 2 H2 (g) + O2 (g) ⟶ 2 H2O (l)

Chemistry
1 answer:
garik1379 [7]3 years ago
8 0

Explanation:

https://socratic.org/questions/using-the-equation-2-h2-o2-2-h2o-determine-how-many-grams-of-oxygen-will-be-need

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Could anyone help me with question 3?
Gwar [14]
Second one i think.......
3 0
3 years ago
How many liters of 15.0 molar NaOH stock solution will be needed to make 17.5 liters of a 1.4 molar NaOH solution? Show the work
strojnjashka [21]
2.0 L
The key to any dilution calculation is the dilution factor

The dilution factor essentially tells you how concentrated the stock solution was compared with the diluted solution.

In your case, the dilution must take you from a concentrated hydrochloric acid solution of 18.5 M to a diluted solution of 1.5 M, so the dilution factor must be equal to

DF=18.5M1.5M=12.333

So, in order to decrease the concentration of the stock solution by a factor of 12.333, you must increase its volume by a factor of 12.333by adding water.

The volume of the stock solution needed for this dilution will be

DF=VdilutedVstock⇒Vstock=VdilutedDF

Plug in your values to find

Vstock=25.0 L12.333=2.0 L−−−−−

The answer is rounded to two sig figs, the number of significant figures you have for the concentration od the diluted solution.

So, to make 25.0 L of 1.5 M hydrochloric acid solution, take 2.0 L of 18.5 M hydrochloric acid solution and dilute it to a final volume of 25.0 L.

IMPORTANT NOTE! Do not forget that you must always add concentrated acid to water and not the other way around!

In this case, you're working with very concentrated hydrochloric acid, so it would be best to keep the stock solution and the water needed for the dilution in an ice bath before the dilution.

Also, it would be best to perform the dilution in several steps using smaller doses of stock solution. Don't forget to stir as you're adding the acid!

So, to dilute your solution, take several steps to add the concentrated acid solution to enough water to ensure that the final is as close to 25.0 L as possible. If you're still a couple of milliliters short of the target volume, finish the dilution by adding water.

Always remember

Water to concentrated acid →.NO!

Concentrated acid to water →.YES!
8 0
4 years ago
Write the chemical equation of in elements
Scilla [17]

Answer : The balanced chemical reaction will be:

CuO+H_2SO_4\rightarrow CuSO_4+H_2O

Explanation :

As per question when copper(II) oxide react with sulfuric acid then it gives copper(II) sulfate and water.

This reaction is known as double displacement reaction in which cation of two reactants exchange their places to give two different products.

The balanced chemical reaction will be:

CuO+H_2SO_4\rightarrow CuSO_4+H_2O

8 0
4 years ago
How many moles of potassium sulfate are present in a sample that weighs 45.8g?
Nikitich [7]

Answer:

0.263 mol

Explanation:

K2SO4 - potassium sulfate

Molar mass (K2SO4) = 2*39.0983 + 32.065 + 4*15.9994 =

= 174.2592≈174.26 g/mol

45.8 g * 1 mol/174.26 g = 0.263 mol

5 0
3 years ago
What is true of enzymes? They only speed up reactions. They speed up or slow down any reaction in a living thing. They act as ca
muminat
They act as catalysts
7 0
3 years ago
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