Answer:
The electric force on the top charge is
.
Explanation:
Given that,
Electric charges in a thundercloud, ![q_1=q_2=45\ C](https://tex.z-dn.net/?f=q_1%3Dq_2%3D45%5C%20C)
The distance between charges, d = 2.3 km = 2300 m
Let F is the electric force on the top charge. The electric force is given by the formula as :
![F=\dfrac{kq^2}{d^2}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7Bkq%5E2%7D%7Bd%5E2%7D)
![F=\dfrac{9\times 10^9\times (45)^2}{(2300)^2}](https://tex.z-dn.net/?f=F%3D%5Cdfrac%7B9%5Ctimes%2010%5E9%5Ctimes%20%2845%29%5E2%7D%7B%282300%29%5E2%7D)
![F=3445179.58\ N](https://tex.z-dn.net/?f=F%3D3445179.58%5C%20N)
or
![F=3.44\times 10^6\ N](https://tex.z-dn.net/?f=F%3D3.44%5Ctimes%2010%5E6%5C%20N)
So, the electric force on the top charge is
. Hence, this is the required solution.
Answer:
A faster because teens what to drink it more when. they see there parents do it
Answer:
3: force acting on an object over time
Explanation:
The impulse formula is: change in momentum = force x time
Δp = f x t
Answer:
Correct answer: V₂ = 1.79 m/s
Explanation:
Given:
m₁ = 32 kg the mass of the first student
V₁ = 2.4 m/s speed of the first student after pushing
m₂ = 43 kg the mass of the second student student
V₂ = ? speed of the second student after pushing
I₁ = m₁ · V₁ impulse of the first student
I₂ = m₂ · V₂ impulse of the second student
Under the law of impulse maintenance, the total impulse of an object must be constant over time.
Since the total impulse before pushing was equal to zero it must be afterwards.
I₁ + I₂ = 0 ⇒ I₂ = - I₁ ⇒ V₂ = - V₁
Given that the impulses are vectors a sign minus ahead of the first pulse mean, they are opposite directions.
m₂ · V₂ = m₁ · V₁ ⇒ V₂ = (m₁ · V₁) / m₂ = (32 · 2.4) / 43 = 1.79 m/s
V₂ = 1.79 m/s
God is with you!!!
70 Years for the oil to last