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cricket20 [7]
3 years ago
11

Two cars, a and b, are traveling with the same speed of 40. 0 m/s, each having started from rest. Car a has a mass of 1200 kg, a

nd car b has a mass of 2000 kg. Compared to the work required to bring car a up to speed, how much additional work is required to bring car b up to speed?.
Physics
1 answer:
Goshia [24]3 years ago
7 0
W=K_B-K_A
W=m_B v^2/2-m_A v^2/2=(m_B-m_A)v^2/2
W=(2000-1200) 〖40〗^2/2=640000 J=640 kJ.

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You can describe the _______________ of an object by saying it is moving in a straight line or is curved around another object.
velikii [3]

Answer:

You can describe the<u> motion </u>of an object by saying it is moving in a straight line or is curved around another object. You can also describe where an object is by its <u> position </u> in relation to another object. The second object acts as a<u> reference</u> point. When an object changes position, you know it has motion. Motion can also be described by finding an object's <u>speed  </u>or how fast or slow it moves in a certain amount of time. In addition, you can describe the object's speed AND direction together. This is called <u>velocity</u>

Explanation:

In the given answer-

<u>Motion</u> is defined as - the change in the movement or position of any object  or body.

<u>Position</u> is said to be a place or somewhere or a location where any object or body is particularly placed/located or put on.

<u>Reference poin</u>t is a fixed point with regards to which any object or body changes its position. It is also called reference origin.

<u>Speed</u> is defined as the rate of any object covering certain distances. It is a scaler quantity (quantity which depends upon only magnitude).

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3 years ago
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weqwewe [10]
The answer would be 4. All of the above

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3 years ago
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A 12 kg box is at rest on your kitchen counter, which your cat is pawing at with a horizontal force of 40 N. If the coefficient
murzikaleks [220]

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lutik1710 [3]

Coulomb's Law

Given:

F = 3.0 x 10^-3 Newton

d = 6.0 x 10^2 meters

Q1 = 3.3x 10^-8 Coulombs

k = 9.0 x 10^9 Newton*m^2/Coulombs^2

Required:

Q2 =?

Formula:

F = k • Q1 • Q2 / d²

Solution:

So, to solve for Q2

 

Q2 = F • d²/ k • Q1

Q2 = (3.0 x 10^-3 Newton) • (6.0 x 10^2 m)² / (9.0 x 10^9 Newton*m²/Coulombs²) • (3.3x 10^-8 Coulombs)

Q2 = (3.0 x 10^-3 Newton) • (360 000 m²) / (297 Newton*m²/Coulombs)

Q2 = 1080 Newton*m²/ (297 Newton*m²/Coulombs)

Then, take the reciprocal of the denominator and start multiplying

Q2 = 1080 • 1 Coulombs/297

Q2 = 1080 Coulombs / 297

Q2 = 3.63636363636 Coulombs

Q2 = 3.64 Coulumbs

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