Mike Hawk Moe Lester Hugh Janice
For three moles of an ideal gas are taken around the eye, the total work for the cycle is mathematically given as
Wt=1945.475J
<h3>What is the total work F for the cycle.(R=8.31J/molK)?</h3>
Generally, the equation for work is mathematically given as
Wt=wac+Wc+Wba
Therefore
Wac=Pa(Vc-Va)=nR(Tc-Ta)
Wac=3(8.314*192)
Wac=4788.864J
Wcb=P1v1-p2v2/v-1
Wcb-3*8.34*108/0.4
Wcb=-6734.34J
Wab=0
In conclusion,
Wt=wac+Wc+Wba
Wt=4788.864J+0+(-6734.34J)
Wt=+1945.475J
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Answer:
x = 259 Hz
Explanation:
given,
frequency of one tuning fork = 250 Hz
frequency of another tuning fork = 266 Hz
when a tuning fork is sounded together beat frequency heard = 9
let x be the frequency of unknown
x - 250 = 9 Hz..............(1)
x = 259 Hz
when a another tuning fork is sounded together beat frequency heard = 7
266 - x = 7 Hz..............(2)
x = 259 Hz
now, on solving both the equation the frequency comes out to be 259 Hz.
so, The frequency of the tuning fork is equal to 259 Hz
Answer:
Ben's average speed was twice Debby's average speed.
Explanation:
Ben covered a total distance of 16 miles (10+4+2) and Debby covered 8 miles (3+2+2+1) which is half of what Ben covered. As they both reached the place in the same amount of time it tells us Ben was faster.
