Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
7. 233
8. 4
9. 6
10. 5
11. 4
12. 7
13. 7
Answer:
100 :P when u read to fast n then put 2500 lol
Step-by-step explanation:
Answer:
No I dont agree with Mai. As both the slug and snail are moving with constant speed.
Step-by-step explanation:
Given that:
A slug travels 3 centimeters in 3 seconds.
Speed of slug = distance/ time = 3/3 = 1 cms^-1
A slug travels 3 centimeters in 3 seconds.
Speed of snail = distance/ time = 6/6 = 1 cms^-1
Hence both have constant speeds only the time span for snail is increased which gives more distance it doesn't means that it had covered more distance.
i hope it will help you!
