1 1/4
Pretty easy. For me at least.
Answer:
0.293 s
Step-by-step explanation:
Using equations of motion,
y = 66.1 cm = 0.661 m
v = final velocity at maximum height = 0 m/s
g = - 9.8 m/s²
t = ?
u = initial takeoff velocity from the ground = ?
First of, we calculate the initial velocity
v² = u² + 2gy
0² = u² - 2(9.8)(0.661)
u² = 12.9556
u = 3.60 m/s
Then we can calculate the two time periods at which the basketball player reaches ths height that corresponds with the top 10.5 cm of his jump.
The top 10.5 cm of his journey starts from (66.1 - 10.5) = 55.6 cm = 0.556 m
y = 0.556 m
u = 3.60 m/s
g = - 9.8 m/s²
t = ?
y = ut + (1/2)gt²
0.556 = 3.6t - 4.9t²
4.9t² - 3.6t + 0.556 = 0
Solving the quadratic equation
t = 0.514 s or 0.221 s
So, the two time periods that the basketball player reaches the height that corresponds to the top 10.5 cm of his jump are
0.221 s, on his way to maximum height and
0.514 s, on his way back down (counting t = 0 s from when the basketball player leaves the ground).
Time spent in the upper 10.5 cm of the jump = 0.514 - 0.221 = 0.293 s.
Answer:
1 B
2 C
3 E
4 D
5 A
Step-by-step explanation:
1. W is less than Zero
2. W is equal or less than Zero
3. W cannot equal Zero. W is more than Zero or less than Zero
4. W is equal or greater than Zero
5. W is greater than Zero
Answer:
A=6a2=6·52=150in²
Step-by-step explanation:
Answer and Step-by-step explanation: Suppose remaining credit is y and time in minutes is x. To determine a value of y corresponding to a value of x, first find the equation for the function.
Since the function is linear, the equation is of the form: y = mx + b. To determine it:
1) Find slope, or inclination, of the line:
slope (m) = 
where x's and y's are points of the function.
2) Determine the y-intercept, or b: Use a point of the function, replace them at the equation, y = mx + b, and find b.
3) The equation will be: y = mx + b
With the equation, replace x for the minutes the question is asking and calculate to find the remaining credit.
Th result will be a pair (x,y)
