Hello!
First one we can use that PE=mgh so we have
4.37*10^5J/(9.12*10^3kg*9.80m/s^2)= 4.89m
Second one we can use Newton’s Second Law
F=ma and in this case F=mg so we have
g= 3.28*10^-2N/6*10^-3kg = 5.47m/s^2
Hope this helps. Any questions please ask. Thank you.
Answer:
Option (D)
Explanation:
In the projectile motion
Horizontal distance = horizontal velocity × time
3.3 = u × 0.66
u = 5 m/s
Muzzle velocity is 5 m/s
A+b(2d*5d)+7654321−2234567
<span>=<span><span>a+<span><span>10b</span><span>d^2</span></span></span>+</span></span>5419754<span>=<span><span><span>(<span><span>10b</span><span>d^2</span></span>)</span>+<span>(a)</span></span>+</span></span>5419754<span>=<span><span><span><span>10b</span><span>d^2</span></span>+a</span>+5419754
</span></span>Answer:<span>=<span><span><span><span>10b</span><span>d^2</span></span>+a</span>+5419754</span></span>
Inertia resists change in its motion( or remains in its existing state of rest) unless that state is changed by an external force.
Answer: 24.4 degrees to the vertical
Explanation:
Vertical component of raindrop speed = 11m/s
Horizontal component of wind = 5m/s
In this case, all we have to do is to use trigonometric ratios of angles to sides as in a triangle
Doing this, we see that
tan (theta) = 5/11
(Where theta is the angle made with the vertical by the rain after impact)
Tan being opposite/adjacent
Arc sin (5/11) gives us 24.44 degrees to the vertical