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torisob [31]
3 years ago
14

In one experiment, the teacher determined that the force on the wire was 2.14 mN

Physics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer:

in ine experiment the teacher determined

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4. How long would it take for a water balloon to fall 39 m if we dropped it starting from rest down an
Paraphin [41]

Answer:

Around 2.8212 sec

Explanation:

Given the eqn x=1/2at^2+vot

your vo=0

39=1/2(-9.8)t^2

=7.95=t^2

=2.82sec

8 0
3 years ago
If we increase the driving frequency in a circuit with purely resistive load, how do the amplitudes VR and IR change?
Lady_Fox [76]

Answer:

V = I R    

expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

Explanation:

In a purely resistive circuit, the Ohm relation, m for which

          V = I R

We see that the previous expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

This does not happen in circuits with capacitors or inductors where there is an explicit dependence on frequency.

3 0
3 years ago
The ________ is located inside the outdoor condenser unit and receives the low-pressure refrigerant vapor through the suction li
dusya [7]

Answer:

Compressor

Explanation:

Compressor - the compressor is a unit that placed at the inner side of the condenser. The main function of the compressor is to increase the pressure by reducing the volume of air. And this reduced volume of air is compressed for the cleaning purpose of the air tube. While condenser is used for heat exchange which converts steam into liquid form.  

It is advisable not to operate the compressor when the outside temperature is below 65 degrees F.

6 0
3 years ago
A solid conducting sphere has net positive charge and radius r = 0.800 m . At a point 1.20 m from the center of the sphere, the
Serga [27]

here we have to calculate the net positive charge present on he surface  of the conducting  sphere.

as the sphere is a conducting one the,the charge will be stored on its surface.

though the charge is present at the surface,still it will behave just like the total charge is concentrated at the centre of the sphere.

the electric field at outside of the sphere is E=\frac{1}{4\pi\epsilon} \frac{q}{r^2}

as E= \frac{-dv}{dr}

so V=\frac{1}{4\pi\epsilon} \frac{q}{r}

here V=27 volt,radius of sphere is 0.800 m and the point at which the potential is considered is at 1.20 m from th centre of the sphere.hence the point is at the outside of the sphere .

hence we have 27=\frac{1}{4\pi\epsilon} \frac{q}{1.20}

                            q=27×\frac{1}{9*10^{9} }* 1.20 coulomb

                                =3.6×10^{-9} coulomb [ans]

5 0
3 years ago
Which quantity can be calculated using the equation E=mc2
EastWind [94]

Well, the equation describes the relationship among
three physical quantities ...

E . . . energy
m . . . mass
c . . . the speed of light.

Speaking strictly algebraically, if you know any two of them,
you can use the equation to calculate the third one.

5 0
4 years ago
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