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Simora [160]
3 years ago
13

A+b(2d*5d)+7654321-2234567

Physics
1 answer:
Mekhanik [1.2K]3 years ago
6 0
A+b(2d*5d)+7654321−2234567
<span>=<span><span>a+<span><span>10b</span><span>d^2</span></span></span>+</span></span>5419754<span>=<span><span><span>(<span><span>10b</span><span>d^2</span></span>)</span>+<span>(a)</span></span>+</span></span>5419754<span>=<span><span><span><span>10b</span><span>d^2</span></span>+a</span>+5419754

</span></span>Answer:<span>=<span><span><span><span>10b</span><span>d^2</span></span>+a</span>+5419754</span></span>
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Dans un tube en U contenant du mercure ,on verse de l'autre côté de l'acide sulfurique de densité 1,84 et de l'autre côté de l'a
Iteru [2.4K]

Explanation:

Unclear question. The clear rendering reads;

"Into a U-tube containing mercury, pour on the other side sulfuric acid of density 1.84 and on the other side alcohol of density 0.8 so that the levels are in the same horizontal plane. The height of the acid above the mercury being 24 cm. What is the height of the bar and what variation of the level of the acid, when the mercury density is 13.6?

6 0
2 years ago
Can a goalkeeper at his goal kick a soccer ball into the opponent’s goal without the ball touching the ground? The distance will
zmey [24]

The goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

Explanation:

Consider the vertical motion of ball,

We have equation of motion v = u + at

     Initial velocity, u  = u sin θ

     Final velocity, v =  0 m/s    

     Acceleration = -g

     Substituting

                      v = u + at  

                      0 = u sin θ - g t

                      t=\frac{usin\theta }{g}

This is the time of flight.

Consider the horizontal motion of ball,

        Initial velocity, u =  u cos θ

        Acceleration, a =0 m/s²  

        Time, t=\frac{usin\theta }{g}  

     Substituting

                      s = ut + 0.5 at²

                      s=ucos\theta \times \frac{usin\theta }{g}+0.5\times 0\times (\frac{usin\theta }{g})^2\\\\s=\frac{u^2sin\theta cos\theta}{g}\\\\s=\frac{u^2sin2\theta}{2g}

This is the range.

In this problem

              u = 30 m/s

              g = 9.81 m/s²

              θ = 45° - For maximum range

Substituting

               s=\frac{30^2\times sin(2\times 45)}{2\times 9.81}=45.87m

Maximum horizontal distance traveled by ball without touching ground is 45.87 m, which is less than 95 m.

So the goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground

6 0
3 years ago
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Vsevolod [243]

Answer:

The answer is for your question is :

Explanation:

True

4 0
2 years ago
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Answer:

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The planet has to do work "against" the field to get to "C".

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3 0
2 years ago
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Answer:

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Explanation:

Have a good day.

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