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kupik [55]
3 years ago
5

A 1430 kg car speeds up from 7.50 m/s to 11.0 m/s in 9.30 s. Ignoring friction, how much power did that require?(unit=W)PLEASE H

ELP
Physics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

4982.8 W

Explanation:

Given the mass of the car = 1430 kg

initial speed = 7.5m/sec

final speed = 11.0 m/sec

time = 9.30sec

Assuming constant accelration a We know that

v=u+at

11=7.5+9.3a

a=0.376 m/sec^2

We know that F=ma

F= 1430*0.376 = 538.2N

We know that v^2-u^2=2as

11^2-7.5^2=2*0.376*s

s= 86.10m

We know that work(W)=F*s

W= 538.2*86.10 = 46339.02J = 46.34KJ

We know that power= \frac{work}{time} = \frac{46.34}{9.3}=4.982 KW

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Answer:

<h2>50m/s^2</h2>

Explanation:

Step one:

given data

initial velocity u= 0m/s since the ball is at rest

time of contact t= 0.3s

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Required

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substitute our given data

15=0+a*0.3

15=0.3a

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a=15/0.3

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<u>The average acceleration is 50m/s^2</u>

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2 years ago
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Which of the following statements best explains why a book resting on a table is in equilibrium?
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A 15.0-kg child descends a slide 2.40 m high and reaches the bottom with a speed of 1.10 m/s .
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The thermal energy that is generated due to friction is 344J.

<h3>What is the thermal energy?</h3>

Now we know that the total mechanical energy in the system is constant. The loss in energy is given by the loss in energy.

Thus, the kinetic energy is given as;

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The thermal energy is; 352.8 J - 9.1 J = 344J

Learn more about thermal energy due to friction:brainly.com/question/7207509

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