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kupik [55]
3 years ago
5

A 1430 kg car speeds up from 7.50 m/s to 11.0 m/s in 9.30 s. Ignoring friction, how much power did that require?(unit=W)PLEASE H

ELP
Physics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer:

4982.8 W

Explanation:

Given the mass of the car = 1430 kg

initial speed = 7.5m/sec

final speed = 11.0 m/sec

time = 9.30sec

Assuming constant accelration a We know that

v=u+at

11=7.5+9.3a

a=0.376 m/sec^2

We know that F=ma

F= 1430*0.376 = 538.2N

We know that v^2-u^2=2as

11^2-7.5^2=2*0.376*s

s= 86.10m

We know that work(W)=F*s

W= 538.2*86.10 = 46339.02J = 46.34KJ

We know that power= \frac{work}{time} = \frac{46.34}{9.3}=4.982 KW

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Just do the multiplication, and you get

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A 30.0 kg dolphin decelerates from 12.0 to 7.00 m/s in 2.60 s to join another dolphin in play. What average force (in N) was exe
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Answer:

Force is 57.69 N to the opposite direction of motion of dolphin.

Explanation:

We have force is the product of mass and acceleration.

That is    

                 Force = Mass x Acceleration

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We have equation of motion, v = u + at

Final velocity, v = 7 m/s

Initial velocity, u = 12 m/s

Time, t = 2.60 s

Substituting

                   7 = 12 + a x 2.6

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Force,   F = 30 x -1.92 = -57.69 N

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puteri [66]

Answer:

1449 K

Explanation:

The surface temperature of a star is related to its peak wavelength by Wien's displacement law:

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So the surface temperature of the star is

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frosja888 [35]

Answer:

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We have,

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