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nexus9112 [7]
2 years ago
13

4. A construction worker needs to put

Mathematics
1 answer:
serg [7]2 years ago
8 0

Answer:

Step-by-step explanation:

If the window is truly a rectangle then both diagonals are equal. That's one of the properties of a rectangle.

Answer: 10 feet

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Ellen needs to buy 180 inches of ribbon to wrap a present. The store sells ribbon only in whole yards. How many yards does Ellen
exis [7]
If very 36 inches is a yard and you divide 180 inches by 36 you would be left with 5 so see would need 5 yards of ribbon  
4 0
3 years ago
Find functions f and g such that h = g ∘ f. (note: the answer is not unique. enter your answers as a comma-separated list of fun
polet [3.4K]

It is given in the question that

h(x) = (fog)(x) = x^2 -81

And x^2 -81

can also be written as

(x^2 -40) -41

Therefore,

(fog)(x) = (x^2 -40)-41

f(g(x)) = (x^2 -40)-41

That gives,

g(x) = x^2 -40, f(x) = x-41

7 0
3 years ago
1. Factor x²+5x-24 <br> 2. Factor 2n²-5n-3
Fynjy0 [20]

Given problems;

 1. Factor;  x²+5x-24

To factor this equation, we must understand that this is a quadratic equation.

A quadratic equation usually has two roots.

  • Equate to zero;

            x²+5x-24 = 0

  • Then find two numbers whose product is -24 and their sum is +5

  the numbers are  +8 and -3

 then replace 5x with the number;

        x² + 8x - 3x - 24  = 0

Now factorize;

     x(x +8) - 3(x + 8) = 0

        (x-3)(x+8)  = 0

Factoring gives (x-3)(x+8)

2. Factor 2n² - 5n -3;

Equate to zero;

   2n² - 5n -3 = 0

Find the number whose sum is -5 and the product gives -6( 2 x -3);

      the number is -6 and +1;

   2n² - 6n + n -3 = 0

   2n(n-3) + 1(n-3) = 0

     (2n + 1)(n-3) = 0

The factor of the equation is (2n + 1)(n-3).

6 0
3 years ago
The length of the road is 1000 miles. If 1 inch represents 100 miles, what is the length of the road on the map?
-BARSIC- [3]

Answer:

10 Inches.

Step-by-step explanation:

1000 divided by 100 = 10.

6 0
3 years ago
Read 2 more answers
Find a polynomial of degree 4 and the zeros are -2, 4, 4, 8
777dan777 [17]

Required polynomial of degree four having zeros as -2 , 4 , 4 , 8 is f(x)=x^{4}-14 x^{3}+48 x^{2}+32 x-256

<h3><u>Solution:</u></h3>

Need to determine a polynomial of degree 4 and the zeros are -2, 4 , 4 and 8

Let the required polynomial be represented by f(x)

The factor theorem describes the relationship between the root of a polynomial and a factor of the polynomial.

If the polynomial p(x) is divided by cx−d and the remainder, given by p(d/c), is equal to zero, then cx−d is a factor of p(x).

-2 is zero of a polynomial means when x = -2, f(-2) = 0, so from factor theorem we can say that  

=> x = -2 that is x + 2 = 0 is factor of polynomial f(x)

4 is zero of a polynomial means when x = 4, f(4) = 0 , so from factor theorem we can say that  

=> x = 4 that is x -4 = 0 is factor of polynomial f(x)

4 is zero of a polynomial means when x = 4, f(4) = 0 , so from factor theorem we can say that  

=> x = 4 that is x -4 = 0 is factor of polynomial f(x)

8 is zero of a polynomial means when x = 8, f(8) = 0 , so from factor theorem we can say that  

=> x = 8 that is x -8 = 0 is factor of polynomial f(x)

So now we have four factors of polynomial f(x) that are (x + 2), (x -4) , (x -4) and (x – 8)

And as given that degree of polynomial f(x) is 4  

Now f(x) is equal to product of factors

\begin{array}{l}{\Rightarrow f(x)=(x+2)(x-4)^{2}(x-8)} \\\\ {=>f(x)=(x+2)\left(x^{2}-8 x+16\right)(x-8)} \\\\ {=>f(x)=(x+2)\left(x^{3}-8 x^{2}+16 x-8 x^{2}+64 x-128\right)} \\\\ {=>f(x)=(x+2)\left(x^{3}-16 x^{2}+80 x-128\right)} \\\\ {=>f(x)=x\left(x^{3}-16 x^{2}+80 x-128\right)+2\left(x^{3}-16 x^{2}+80 x-128\right)} \\\\ {=>f(x)=x^{4}-16 x^{3}+80 x^{2}-128 x+2 x^{3}-32 x^{2}+160 x-256} \\\\ {=>f(x)=x^{4}-14 x^{3}+48 x^{2}+32 x-256}\end{array}

Hence required polynomial of degree four having zeros as -2 , 4 , 4 , 8 is f(x)=x^{4}-14 x^{3}+48 x^{2}+32 x-256

7 0
3 years ago
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