Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:
41 litters to gallons is 10.8311
3.5 gallons to litters is 13.2489
Answer:
5 people bought the $17 steak and 1 person bought the $14 chicken.
Step-by-step explanation:
Answer:
7/10 is 70%
67/100 is 67% (there is more than one right answer to this one)
9/2 is 450%
Answer:
x<6
Step-by-step explanation:
96 > 4((5x - 6)
96 > 20x - 24
96+24>20x
120>20x
6>x
Or x<6