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allochka39001 [22]
3 years ago
5

Plz help i will mark brainliest

Mathematics
2 answers:
Andru [333]3 years ago
8 0
1. -|12|
2. -5
3.-1
4.|-1|
5.12
bulgar [2K]3 years ago
4 0

Answer:

1. -|12|

2. -5

3. -1

4. |-1|

5. 12

Step-by-step explanation:

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Daniel drives his car 374 miles using 22 gallons of gas. How many miles per gallon does his car get?
olya-2409 [2.1K]
He gets 374 miles on 22 gallons.

The amount of miles per gallon is 374/22 = 17.
4 0
4 years ago
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Carl always studies financial statements published by various companies before buying their stocks. How would you categorize Car
navik [9.2K]
i think it is B because <span>is a person outside of an organization who does not directly run its operations and uses financial or accounting information about that company to make decision.</span>
7 0
3 years ago
Make a table of values for f(x) = 18x2 + 10x + 1.
serg [7]

Answer/step-by-step explanation:

To make a table of values, substitute each value of x into the given equation function f(x) = 18x^2 + 10x + 1

For x = -3,

f(-3) = 18(-3)^2 + 10(-3) + 1

f(-3) = 18(9) + (-30) + 1

f(-3) = 162 - 30 + 1 = 133

For x = -2,

f(-2) = 18(-2)^2 + 10(-2) + 1

f(-2) = 18(4) + (-20) + 1

f(-2) = 72 - 20 + 1 = 53

For x = -1,

f(-1) = 18(-1)^2 + 10(-1) + 1

f(-1) = 18(1) + (-10) + 1

f(-1) = 18 - 10 + 1 = 9

For x = 0,

f(0) = 18(0)^2 + 10(0) + 1

f(0) = 18(0) + 0 + 1

f(0) = 0 - 0 + 1 = 1

For x = 1,

f(1) = 18(1)^2 + 10(1) + 1

f(1) = 18(1) + 10 + 1

f(1) = 18 + 10 + 1 = 29

For x = 2,

f(2) = 18(2)^2 + 10(2) + 1

f(2) = 18(4) + 20 + 1

f(2) = 72 + 20 + 1 = 93

For x = 3,

f(3) = 18(3)^2 + 10(3) + 1

f(3) = 18(9) + 30 + 1

f(3) = 162 + 30 + 1 = 193

7 0
3 years ago
What is the value of x? <br><br> 63<br><br> 92<br><br> 58<br><br> 121
mojhsa [17]
63 because it is the only answer that makes sense.

6 0
3 years ago
Read 2 more answers
What does the fundamental theorem of algebra state about the equation 2x^2−6x+10=0 ?
Temka [501]

Answer:

B. The fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. The roots are ​ x=3±i√11/2 .  

Step-by-step explanation:

We know that,

Fundamental theorem of algebra states that ' a polynomial of degree n will have n number of roots'.

Since, the polynomial y=2x^{2}-6x+10 has degree 2, so it will have 2 roots.

We know that the polynomial ax^{2}+bx+c=0 has roots given by x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}.

So, the roots of polynomial 2x^{2}-6x+10=0 will be,

x=\frac{6 \pm \sqrt{(-6)^{2}-4 \times 2 \times 10}}{2 \times 2}

i.e. x=\frac{6 \pm \sqrt{36-80}}{4}

i.e. x=\frac{6 \pm \sqrt{-44}}{4}

i.e. x=\frac{6 \pm 2i \sqrt{11}}{4}

i.e. x=3 \pm \frac{\sqrt{11}i}{2}

Hence, the roots are given by 3 \pm \frac{\sqrt{11}i}{2}

So, option B is correct.

5 0
3 years ago
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