Suppose y varies directly with x, and y=-4 when x=8. Find the y when x=14

What is 7a^{2} - a^{2} + 16

prohojiy [21]

Answer:can u pls help answer my question 4d+15 is greater than or equal to -1

Step-by-step explanation:

3 0

3 years ago

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4. Let f(x) = 2x +1 and g(x) = x². Find (gºf)(a).

PolarNik [594]

Answer:

Step-by-step explanation:

hello :

f(x) = 2x +1 and g(x) = x².

(gºf)(a)= g(f(a)) = g(2a+1) = (2a+1)² = 4a²+4a+1

3 0

3 years ago

Determine if the following functions are increasing or decreasing, and compare their rates of change. A. Both functions are incr

adoni [48]

Answer:

D is the answer

Step-by-step explanation:

The both are - 2 slopes hope this helps!:)

4 0

2 years ago

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PLS ANSWER QUICK PLS PLS PLS ILL GIVE BRAINLIEST TO FIRT ANSWER!!

Softa [21]

Answer:

2

Step-by-step explanation:

6 0

2 years ago

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Define z_alpha to be a z-score with an area of alpha to the right. For Example: z_0.10 means P(Z > z_0.10) = 0.10. We would a

Reptile [31]

Answer:

a) P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

And for this case the two values are : $z_{crit}= \pm 1.96$

b) P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates $\alpha/2$ of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

c) For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got $z_{\alpha/2}=1.64$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Part a

P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

And for this case the two values are : $z_{crit}= \pm 1.96$

Part b

P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates $\alpha/2$ of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

Part c

For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got $z_{\alpha/2}=1.64$

6 0

3 years ago