Question

Find the solution of Z^5=32 whose argument is strictly between 0 and 90 degrees

Answer 1

Answer:

$\|r\| = 32$, $\theta = 0\,rad$

Step-by-step explanation:

This complex expression is computed from the De Moivre expression:

$z^{5} = 32\cdot (\cos 5x + i \cdot \sin 5x)$

Given that resultant expression is entirely real, the expression is simplified into this form:

$32 = 32\cdot \cos 5x$

$\cos 5x = 1$

The angle is 0 radians.