The sample size needed to obtain a margin of error of 0.05 for the estimation of a population proportion is 384.
Given margin of error of 0.05 and confidence interval of 95%.
We have to find the sample size needed to obtain a margin of error of 0.5 with confidence level of 95%.
Margin of error is the difference between real values and calculated values.
The formula of margin of error is as under:
Margin of error=z*σ/
where
z is the critical value of z for given confidence level
n is sample size
σ is population standard deviation
We have not given population standard deviation so we will use the following formula:
Margin of error=z*/
We have to find z value for 95% confidence level.
z value=1.96
We know that <=1/2
put =1/2
Margin of error=1.96*1/2/
0.05=1.96*0.5/
=0.98/0.05
=19.6
squaring both sides
n=384.16
After rounding off we will get
n=384.
Hence the sample size needed to obtain a margin of error of 0.05 is 384.
Learn more about margin of error at brainly.com/question/10218601
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I think you multiply 17×9 which equals 153 and then multiply 68×36 which equals 2,448 and then add 2,448+153 which equals 2,601
Answer:
4 < 7
Step-by-step explanation:
-7 + 11 =
11 - 7 =
4
-4 + 11 =
11 - 4 =
7
4 < 7
Angles of the parallelogram which is given in the problem are:α = 49° + 17 °= 66°
β = 180° - 66° = 114°
x - length of the longest side of the parallelogram;
Use the Sine Law:x / sin 49° = 20/ sin 17°
x / 0.7547 = 20 / 0.2924
0.2924 x = 15.094
x = 15.094 : .2924
x = 51.62 is the longest side of the parallelogram.
Answer:
don't know lol
Step-by-step explanation:
don't know don't ask lol