Answer: Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the distribution of the sample is consistent with the distribution of the state populations.
Explanation:
The null and alternative hypotheses are:
The sample of 1000 subjects has a distribution that is consistent with the distribution of state populations.
The sample of 1000 subjects does not have a distribution that is consistent with the distribution of state populations.
Under the null hypothesis, the test statistic is:

From the attachment, we clearly see the chi-square statistic is:

Now we have to find the chi-square critical value at 0.05 significance level for df = n - 1 = 4-1=3. Using the chi-square distribution table, we have:

Since the chi-square statistic is greater than the chi-square critical value, we therefore reject the null hypothesis and there is sufficient evidence to warrant rejection of the claim that the distribution of the sample is consistent with the distribution of the state populations
Answer:
3/8
Step-by-step explanation:
Fraction of green pencils = 1 -1/4 + 3/8 =3/8
Hint: 423 = (40 + 2)3; therefore, x = 40 and y = 2.
Eef. (dont make me miss unus annus again)
<span>With 1026 being the mean score on the SAT and StDev of 209, Jessica has a score of 799/209 z-scores above the mean. Her z-score would be 3.823. The mean of the ACT and StDev are 20.8 and 4.8, respectively. A 28 ACT score would be 7.2/4.8 z-scores above the mean, for a z = 1.500. This means that Jessica has the higher z-score.</span>