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3241004551 [841]
3 years ago
9

The office worker can stamp 25 letters per minute.

Mathematics
2 answers:
drek231 [11]3 years ago
6 0

For this case, we can solve the problem by using the following ratio:

\frac {25} {1} = \frac {x} {5}

Where,

x: number of letters in 5 minutes

Clearing the value of x we have:

x = 5 (\frac {25} {1})\\x = 5 * 25\\x = 125

Answer:

At that rate, the number of letters that the worker can stamp in 5 min is 125.

Option D.

sweet-ann [11.9K]3 years ago
5 0
You set it up into a fraction equation. 25 over 1 = x over 5. The numerator is the letters and the denominator is the minutes. You then cross multiply and then you get x=125. That is your answer. Hope that helps.
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Answer:

She gave 7 stickers.13+7=20.sarah has 20 stickers

Step-by-step explanation:

Divide 28 by 4

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2 years ago
What is the solution to the system of equations graphed below?<br> y=-4x + 33<br><br> y=5/3x-1
Black_prince [1.1K]

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x = 6

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This is the correct answer. Not satisfied? Check out this answer expert verified answer of the same question but with a step-by-step explanation. This answer is just a simple version of rocioo's correct answer.

Expert Verified Answer (of this same question but with a step-by-step explanation):

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blsea [12.9K]

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Step-by-step explanation:

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3 years ago
An amount was shared in the ratio 8:6:9:14:12.The largest share was56.What was the total amount shared?
lutik1710 [3]

Answer:

196

Step-by-step explanation:

Since the largest share was 56 and the largest ratio is 14, then

56 ÷ 14 = 4 ← value of 1 part of the share, thus

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6 parts = 6 × 4 = 24

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6 0
3 years ago
Help me please guys.
Alex_Xolod [135]
15.04 degrees or answer A is correct.


The Law of Sines is the relationship between the sides and angles of non-right (oblique) triangles . Simply, it states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all sides and angles in a given triangle. The formula for it is A=b•sin a/sin b.


You can transform the law of sines formulas to solve some problems of triangulation (solving a triangle). You can use them to find:

The remaining sides of a triangle, knowing two angles and one side.
The third side of a triangle, knowing two sides and one of the non-enclosed angles. In some cases (ambiguous cases) there may be two solutions to the same triangle. If the following conditions are fulfilled, your triangle may be an ambiguous case:
You only know the angle α and sides a and c;
Angle α is acute (α < 90°);
a is shorter than c (a < c);
a is longer than the altitude h from angle β, where h = c * sin(α) (a > c * sin(α)).

I hate useless complicated math lol ;)
5 0
3 years ago
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