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Ghella [55]
3 years ago
6

How do you subtract when there are zero's at the end? For ex. 1000-325 how'd you borrow from 1000?

Mathematics
2 answers:
Alexandra [31]3 years ago
4 0
675. Just subtract. 1000
- 325
Set it up like this.
Karolina [17]3 years ago
4 0
You borrow from the one there maybe zeros but its still a value or borrow from the zero next to the one and then borrow from the one hope it helps :)
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A circle is described by the equation x2 y2 14x 2y 14 = 0. what are the coordinates for the center of the circle and the length
bearhunter [10]

Answer:

length is (-7,-1) and radius is 6

Step-by-step explanation:

We are given the expression of the equation of a circle that is

x2 + y2 + 14x + 2y + 14 = 0.

Using completing the squares:

x2 + y2 + 14x + 2y + 14 = 0(x+7)^2 + (y+1) ^2 = -14 + 49 + 1(x+7)^2 + (y+1) ^2 = 36 center thus is at (-7,-1) and the radius is equal to square root of 36 equal to 6.

6 0
10 months ago
Given the following functions, find and simplify (f • g)(x) f(x)=—x+3 g(x)=-x-1
Hitman42 [59]

Answer:

(f\circ g)(x)= x + 4

Step-by-step explanation:

<u>Composite Function</u>

Given f(x) and g(x) as real functions, the composite function (f\circ g)(x) is defined as:

(f\circ g)(x)=f(g(x))

It can be found by substituting g into f.

We are given the functions:

f(x) = -x + 3

g(x) = -x -1

Find

(f\circ g)(x)=f(g(x))= - (-x -1) + 3

Removing parentheses:

(f\circ g)(x)= x + 1 + 3

Simplifying:

\mathbf{(f\circ g)(x)= x + 4}

5 0
3 years ago
WILL GIVE BEST RESPONSE
tino4ka555 [31]
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1, 
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
<span>
</span>
4 0
3 years ago
Carlo borrows 4180 add a rate of 4.1% Per year compounded annually he does not start payments until after 2.8 years which of the
olga_2 [115]

Answer:497.76

Step-by-step explanation:

3 0
3 years ago
There are 135 people and three door prizes. how many ways can door prizes of $7,500, $750 and $75 be distributed?
igomit [66]

Answer: 2405970 ways

Step-by-step explanation:

When the order of selecting r individuals out of n individual , we use permutations.

The number of permutations of r things taking out of n things is given by :-

^nP_r=\dfrac{n!}{(n-r)!}

Given : There are 135 people and three door prizes .

i.e. n= 135 , r= 3

Then, the total number of ways = ^{135}P_3=\dfrac{135!}{(135-3)!}

=\dfrac{135\times134\times133\times132!}{132!}\\\\=135\times134\times133\\\\=2405970

Hence, there are 2405970 ways to distribute door prizes of $7,500, $750 and $75 .

6 0
3 years ago
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