U r going to subtract 3 from each side of the equation....leaving you with :
x^2 + 2x = -3
Answer:
ΔHFG≅ΔSUT
Step-by-step explanation:
You just have to match up the sides and the angle.It's easier to color code them.
For example:
Segment SU would be congruent with HF. (both would be blue, just example color)
Angle U is congruent to angle F (red)
UT congruent to FG (green)
<span>4. Simplify the expression.
sine of x to the second power minus one divided by cosine of negative x</span>
<span>(1−sin2(x))/(sin(x)−csc(x))<span>
</span>sin2x+cos2x=1</span>
<span>1−sin2x=cos2x<span>
</span>cos2(x)/(sin(x)−csc(x))</span>
<span>csc(x)=1/sin(x)</span>
<span>cos2(x)/(sin(x)− 1/sin(x))= cos2(x)/((sin2(x)− 1)/sin(x))</span>
<span>sin2(x)− 1=-cos2(x)</span>
<span>cos2(x)/(( -cos2(x))/sin(x))
=-sin(x)</span>
<span>
the answer is the letter a)
-sin x
</span><span>
5. Find all solutions in the interval [0, 2π). (6 points)sin2x + sin x = 0</span> using a graphical tool
the solutions
x1=0
x2=pi
<span>x3=3pi/2
the answer is the letter </span><span>
D) x = 0, π, three pi divided by two</span>
Answer:80students
Step-by-step explanation:
Using set notation concept,
n(U) be the total number of student = 200
n(AnS') be those that earned Bachelor in Art only= 120
n(A'nS) be those that earned Bachelor in Science only= 40
n(AnS) be students that earned both degrees.
Using the formulae below to calculate n(AnS) first;
n(AuS)=n(A'nS)+ n(AnS)+n(AnS')
200=40+n(AnS)+120
200=160+n(AnS)
n(AnS)=40
This shows that 40students earned bachelor in both degrees
Those that earned Bachelor in science degree will then be n(A'nS)+n(AnS) i.e 40+40 =80students.
NB: A' means complement of A(A not included)
'n' denote intersection and 'u' denote union.
Answer:

Step-by-step explanation:
We are asked to find the length of the third side in a triangle, given the other 2 sides.
Since this is a right triangle (note the small square in the corner of the triangle representing a 90 degree /right angle), we can use the Pythagorean Theorem.

In this theorem, <em>a</em> and <em>b</em> are the legs of the triangle and <em>c</em> is the hypotenuse.
We know that the unknown side (we can say it is a) and the side measuring 5 are the legs because they form the right angle. The side measuring 10 is the hypotenuse because it is opposite the right angle.
Substitute the values into the formula.

Solve the exponents.
- (5)²= 5*5 = 25
- (10)²= 10*10= 100

We are solving for a, so we must isolate the variable. 25 is being added to a. The inverse operation of addition is subtraction, so we subtract 25 from both sides.



a is being squared. The inverse of a square is the square root, so we take the square root of both sides.



Round to the nearest tenth. The 6 in the hundredth place tells us to round the 6 up to a 7 in the tenth place.

The length of the third side is approximately <u>8.7</u>