Answer:
THE MASS OF NITROGEN GAS IN THIS CONDITIONS IS 0.0589 g
Explanation:
In an ideal condition
PV = nRT or PV = MRT/ MM where:
M = mass = unknown
MM =molar mass = 28 g/mol
P = pressure = 2 atm
V = volume = 25 mL = 0.025 L
R = gas constant = 0.082 L atm/mol K
T = temperature = 290 K
n = number of moles
The gas in the question is nitrogen gas
Molar mass of nitrogen gas = 14 * 2 = 28 g/mol
Then equating the variables and solving for M, we have
M = PV MM/ RT
M = 2 * 0.025 * 28 / 0.082 * 290
M = 1.4 / 23.78
M = 0.0589 g
The mass of the nitrogen gas at ideal conditions of 2 atm, 25 mL volume and 290 K temperature is 0.0589 g
Answer:
a) increase exponentially.
Explanation:
The vapor pressure is depend only on temperature.
The vapor pressure of liquid does not depend upon amount of liquid. For example whether the liquid is 50 g or 30 g its vapor pressure will remain same according to the temperature.
The temperature and vapor pressure have exponential relationship. As the temperature of liquid increases its vapor pressure also goes to increase. When the temperature of liquid goes to decrease its vapor pressure also decreases.
The change in vapor pressure of substance when temperature changes is given as,
ln P₂/P₁ = ΔH(va)/R (1/T₁ - 1/T₂)
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Hope this helps~!
~{Oh Mrs.Believer}
Answer:
500,050000 years
Explanation:
Given that :
Rate of Accumulation = 3cm/ 1000 years
Height of seamounts = 1.5km
Representing height of seamounts in cm;
(1.5 *1000 * 100) = 1500150 cm
Time taken = height / rate
Time taken = (1500150 cm / 3cm) * 1000
Time taken = 500,050000 years
