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4 years ago

The lock-and-key mechanism refers to

Chemistry

2 answers:

miskamm [114]4 years ago

5 0

Answer:

A). The complementary shapes of an enzyme and a substrate.

Explanation:

The Lock-and-key mechanism was proposed by Emil Fischer for the first time and characterized as the metaphor which helps in elucidating the specificity of the enzymatic reactions. In this metaphor, the lock is described as the enzyme while 'key' is characterized as the substrate which the enzyme acts upon. If the key is not appropriately sized, it will not fit into the active site i.e. the keyhole of the lock or enzyme and reaction will not take place. Thus, <u>option A</u> is the correct answer.

sweet-ann [11.9K]4 years ago

5 0

The complementary shapes of an enzyme and substrate

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A sample of seaweed contains 1 liter of water and has 50 grams of salt dissolved in its cells. The seaweed is placed in a soluti

masha68 [24]

seaweed having 50 g salt in 1 L water. The bucket contains 150 g of salt in 2 L of water

amount of water present in bucket is twice to amount of water in weed

$V¬_water bucket=2×V_water weed$

At equilibrium, volume of water in weed is x and volume in bucket is y but concentration remain same as follows:

$50 /x=150 /y\\ Y = 3 x$

At equilibrium, weed loose z L from 1 L water to bucket containing 2 L as follows:

$(2 + z) = 3 (1-z)\\ (2 + z) = 3 – 3 z\\ Z = 0.25 L$

Thus, Weed will loose 0.25 L of water

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3 years ago

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If a jar of honey sits for a long time, sugar may crystallize in the jar. Describe two possible causes for the crystallization.

n200080 [17]

Dryness and temperature are the primary reasons but also the type of honey.

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4 years ago

Chemistry Question, Don't really know how to do it lol.

Scilla [17]

Answer: 17.2 g

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} HgS=\frac{20.0 g}{233g/mol}=0.085moles$

The balanced chemical equation is:

$4HgS(s)+4CaO(s)\rightarrow 4Hg(l)+3CaS(s))+CaSO_4(s)$

According to stoichiometry :

4 moles of $HgS$ produce = 4 moles of $Hg$

Thus 0.085 moles of $HgS$ will require= $\frac{4}{4}\times 0.085=0.085moles$ of $Hg$

Mass of $Hg=moles\times {\text {Molar mass}}=0.085moles\times 200.6g/mol=17.2g$

Thus 17.2 g of $Hg$ will be produced form 20.0 g of HgS.

3 0

3 years ago

The pain reliever morphine contains 17.900 g C, 1.680 g H, 4.225 g O, and 1.228 g N. Determine the empirical Formula.

JulijaS [17]

Answer: The empirical formula is $C_{17}H_{19}O_3N$

Explanation:

Mass of C= 17.900 g

Mass of H = 1.680 g

Mass of O = 4.225 g

Mass of N = 1.228 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{17.990g}{12g/mole}=1.5moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.680g}{1g/mole}=1.680moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{4.225g}{16g/mole}=0.264moles$

Moles of N = $\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{1.228g}{14g/mole}=0.087moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{1.5}{0.087}=17$

For H = $\frac{1.680}{0.087}=19$

For O = $\frac{0.264}{0.087}=3$

For N = $\frac{0.087}{0.087}=1$

The ratio of C : H: O: N = 17: 19: 3: 1

Hence the empirical formula is $C_{17}H_{19}O_3N$

5 0

3 years ago

21 liters converted to mL

Archy [21]

Answer:

21 = 21000

Explanation:

multiply the volume value by 1000

7 0

3 years ago

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