Answer:
Major product ethoxide ion
Explanation:
- Sodium hydride acts as a strong base towards ethanol.
- Hydride ion abstracts one proton from -OH group in ethanol to produce sodium ethoxide and hydrogen gas.
- It is an example of acid-base reaction where sodium hydride acts as a base and ethanol acts as an acid
- Structure of major organic product i.e. ethoxide ion has been shown below.
Answer:
Measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water
Explanation:
To make 100 mL of 0.001 mM solution from 0.0405mM solution, we need to determine the volume of 0.0405mM solution needed. This can be obtained as follow:
Molarity of stock (M₁) = 0.0405 mM
Volume of diluted (V₂) = 100 mL
Molarity of diluted solution (M₂) = 0.001 mM
Volume of stock solution needed (V₁) =?
M₁V₁ = M₂V₂
0.0405 × V₁ = 0.001 × 100
0.0405 × V₁ = 0.1
Divide both side by 0.0405
V₁ = 0.1 / 0.0405
V₁ = 2.47 mL
Therefore, to make 100 mL of 0.001 mM solution from 0.0405mM solution, measure 2.47 mL of the stock solution (i.e 0.0405 mM) and dilute it to the 100 mL mark with water.
Answer:
3
Explanation:
The amount of mass per given vol
Answer:
K2CO3 = K2O + CO2
Explanation:
In a chemical equation, the number of atoms on the left needs to be balanced with the number of atoms on the right, and there has to be the same number of the same *type* of atom on both sides as well.
On the left:
2 K
1 C
3 O
and on the right,
2 K
1 O
On the right, there are a few atoms missing, specifically, 1 C and 2 O.
The missing atoms then should be added to the side missing the atoms, preferably in a stable molecule. Luckily, CO2 contains exactly 1 C, and 2 O s, and is quite stable. So, a "CO2" has to be added on the left
sorry what us this i don't get it
