<u>Answer:</u> The partial pressure of carbon dioxide at equilibrium is 0.0056 atm
<u>Explanation:</u>
The given chemical equation follows:
<u>Initial:</u> 4.00
<u>At eqllm:</u> 4.00-2x x x
The expression of 
for above reaction follows:
The partial pressure of pure solids and liquids are taken as 1 in the equilibrium constant expression.
We are given:
Putting values in above expression, we get:
Neglecting the value of x = 718.28 because equilibrium pressure cannot be greater than initial pressure
Partial pressure of 
= 0.0056 atm
Hence, the partial pressure of carbon dioxide at equilibrium is 0.0056 atm
<span>V=width∗length∗height</span>
the correct answer to this question is C
Answer:
18.2 g.
Explanation:
You need to first figure out how many moles of nitrogen gas and hydrogen (gas) you have. To do this, use the molar masses of nitrogen gas and hydrogen (gas) on the periodic table. You get the following:
0.535 g. N2 and 1.984 g. H2
Then find out which reactant is the limiting one. In this case, it's N2. The amount of ammonia, then, that would be produced is 2 times the amount of moles of N2. This gives you 1.07 mol, approximately. Then multiply this by the molar mass of ammonia to find your answer of 18.2 g.
