1 1/2 * 3/4 =

Change 1 1/2 to an improper fraction = 3/2

3/2 * 3/4 = 6/4 * 3/4

6/4 * 3/4 = 18/4 = 4 2/4 = 4 1/2

The answer is 4 1/2.

Hope this helped☺☺

4 0

4 years ago

The sum of three consecutive even numbers is 114. what is the smallest of the three numbers?

saul85 [17]

Answer:

Step-by-step explanation:

Let's let n be any number.

If we multiply n by 2, we get 2n. Since anything multiplied by 2 is even, 2n <em>must</em> be even. Therefore, let 2n be our first number.

So, the consecutive even number will be (2n+2) followed by (2n+4).

We know that their sum must be 114. Therefore, we can write the following equation:

$(2n)+(2n+2)+(2n+4)=114$

Solve for n. Combine like terms on the left:

$6n+6=114$

Subtract 6 from both sides:

$6n=108$

Finally, divide both sides by 6. Therefore, the value of n is:

$n=108/6=18$

Therefore, our first even number is 2n or 2(18) which equates to 36.

And the consecutive even numbers will be 38 and 40.

So, the smallest of them, the first term, is 36.

4 0

3 years ago

Read 2 more answers

Pls help with this math problem

valentinak56 [21]

-1.5. -1 1/2. -3/2

yeah so its this i’m 99.98% sure

7 0

2 years ago

Please help if you can thanks ^^

Neko [114]

Given:

AD is an angle bisector in triangle ABC. $m\angle CAB=44^\circ, m\angle ACB=72^\circ, m\angle ABC=64^\circ$ .

To find:

The value of $m\angle ADC$ .

Solution:

AD is an angle bisector in triangle ABC.

$m\angle CAD=m\angle BAD=\dfrac{m\angle CAB}{2}$

$m\angle CAD=m\angle BAD=\dfrac{44^\circ}{2}$

$m\angle CAD=m\angle BAD=22^\circ$

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.

Using angle sum property in triangle CAD, we get

$m\angle CAD+m\angle ADC+m\angle ACB=180^\circ$

$22^\circ+m\angle ADC+72^\circ=180^\circ$

$m\angle ADC+94^\circ=180^\circ$

$m\angle ADC=180^\circ-94^\circ$

$m\angle ADC=86^\circ$

Therefore, the angle of angle ADC is $86^\circ$ .

3 0

3 years ago