What is the slope of the line containing (6,8) and (9,9)?

1 answer:

4 0

To find the slope, you use the following formula: ;
Then, m = ( 8 - 9 ) / ( 6 - 9 ) ;
m = ( - 1 ) / ( - 3 ) ;
m = 1 / 3 ;

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For parallelogram LMNO, please help?

jeyben [28]

m∠L = 5x - 28
m∠N = 3x - 10

  m∠L ≡ m∠N
5x - 28 = 3x - 10
- 3x - 3x
2x - 28 = -10
+ 28 + 28
2x = 18
2 2
x = 9

m∠L = 5x - 28
m∠L = 5(9) - 28
m∠L = 45 - 28
m∠L = 17

m∠N = 3x - 10
m∠N = 3(9) - 10
m∠N = 27 - 10
m∠N = 17

  x + 17 = 180
- 17 - 17
  x = 163

m∠O = 163

3 0

4 years ago

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kykrilka [37]

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8 0

4 years ago

Read 2 more answers

-x -7y = 14 -4x -14y =28

koban [17]

Given:

$\to \bold{-x -7y = 14}\\\\\to \bold{-4x -14y =28}\\\\$

To find:

$\bold{x \ and \ y}=?$

Solution:

$\to \bold{-x -7y = 14}..................... (i) \\\\\to \bold{-4x -14y =28} .................(ii)\\\\$

Solving the equation (i):

$\to \bold{-x -7y = 14} \\\\ \to \bold{-x= 14+7y} \\\\ \to \bold{x= - (14+7y)} \\\\$

Putting the value of x into the equation (ii):

$\to \bold{-4(-(14+7y)) -14y =28} \\\\\to \bold{4(14+7y) -14y =28} \\\\\to \bold{56+28y -14y =28} \\\\\to \bold{56+14y =28} \\\\\to \bold{28+14y =0} \\\\\to \bold{14y =-28} \\\\\to \bold{y =\frac{-28}{14}} \\\\\to \bold{y =-2} \\\\$