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3 years ago

18 × 10 by the third power

2 answers:

7 0

THE answer is 18000.

yes this is the answer.

mafiozo [28]3 years ago

5 0

Answer:

18000

Step-by-step explanation:

10 by the third power is just a 1 and then 3 zeros:

1000

So then we have:

18x1000=18000

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Is the point (1,5) a solution to the equation below?

allochka39001 [22]

Answer:

A. No

Step-by-step explanation:

y = 2x + 4

(5) = 2(1) + 4

5 = 2 + 4

5 = 6 (false statement)

7 0

2 years ago

What is 96 divided by 1.5

Mamont248 [21]

64

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3 0

3 years ago

Read 2 more answers

Lily is a lilypad in a small pond. Lily doubles in size each day. On the 20th day she covers the whole pond. On what day was Lil

svetoff [14.1K]

Answer:

19th day

Step-by-step explanation:

So say Lily was 1 when Lily was planted

First day Lily is 2

Second day Lily is 4

Third day Lily is 8

etc...

See the pattern?

The pattern is 2^x

On the 20th day, Lily was 2^20

So when Lily was half, Lily was 2^20 / 2

2^x = 2^20 / 2

2^x = 2^19

On the 19th day, Lily was half.

8 0

3 years ago

A rectangle and 2 congruent quarter circles were used to make the figure shown. Which measurement is closest to the area of the

dexar [7]

Answer:

109.3

Step-by-step explanation:

7 0

3 years ago

natima [27]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

The store keeps an inventory of 80 shovels, then

x+y+z=80

The store always buy twice as many spade shovels as square, so

x=2z

The total cost of all shovels is

16x+9.60y+12.80z=1,072

a) The system of three equations is

$\left\{\begin{array}{l}x+y+z=80\\ \\x=2z\\ \\16x+9.60y+12.80z=1,072\end{array}\right.$

b) In matrix form this is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)$

c) The determinant is

$\left\|\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right\|=0-32+9.60-0+19.20-12.80=-16$

d) Find three determinants:

$\left\|\begin{array}{ccc}80&1&1\\ 0&0&-2\\ 1,072&9.60&12.80\end{array}\right\|=0-2,144+0-0+1,536-0=-608$

$\left\|\begin{array}{ccc}1&80&1\\ 1&0&-2\\ 16&1,072&12.80\end{array}\right\|=0-2,560+1,072-0+2,144-1,024=-368$

$\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304$

So,

$x=\dfrac{-608}{-16}=38\\ \\y=\dfrac{-368}{-16}=23\\ \\z=\dfrac{-304}{-16}=19$

e) If the store doubled all prices and inventory, then the new matrix is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)$

7 0

3 years ago