All categories

3 years ago

PLEASE PLEASEE HELP ITS PAST DUE AND ITS A TEST ILL GIVE BRAINLIEST

Mathematics

2 answers:

agasfer [191]3 years ago

5 0

Answer:

The length will be letter C, 50 m

Akimi4 [234]3 years ago

4 0

The length is c, 50 m

You might be interested in

Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert

Setler [38]

Answer:

$P(x \ge 5) = 1.000$ ---- At least 5 from marketing departments are extroverts

$P(x=15) = 0.013$ ---- All from marketing departments are extroverts

$P(x = 0) = 0.002$ ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$(a):\ P(x \ge 5)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

Using the complement rule, we have:

$P(x \ge 5) = 1 - P(x < 5)$

So, we have:

$P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)$

$P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}$

$P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}$

$P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}$

$P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153$

$P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103$

So, we have:

$P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103$

$P(x < 5) = 0.00011922283$

Recall that:

$P(x \ge 5) = 1 - P(x < 5)$

$P(x \ge 5) = 1 - 0.00011922283$

$P(x \ge 5) = 0.9998$

$P(x \ge 5) = 1.000$ --- approximated

$(b)\ P(x = 15)$

$n = 15$ --- marketing personnel

$p = 75\%$ --- proportion that are extroverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}$

$P(x=15) = 1 * 0.75^{15} * (0.25)^{0$

$P(x=15) = 0.013$

$(c)\ P(x = 0)$

$n=5$ ---------- computer programmers

$p = 70\%$ --- proportion that are introverts

So, we have:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}$

$P(x = 0) = 1 * 1 * (0.30)^5$

$P(x = 0) = 0.002$

3 0

2 years ago

23. Two coins are tossed. Alan gets a point if the coins match and Sondra gets a point if they do not match.

Keith_Richards [23]

Answer:

C. They have the same chance of winning.

Step-by-step explanation:

Probability (2 tails) = 1/2 * 1/2 = 1/4

Probability( 2 heads = 1/2 * 1/2 = 1/4.

Therefore the Probability they match = 1/4 + 1/4 = 1/2.

The probability of they don't match = 1 - 1/2 = 1/2 because all probabilities add up to 1. There are only 4 possible results and their probabilities must add up to 1.

5 0

3 years ago

Read 2 more answers

Solve -3(x+5) = -9 solve

Bumek [7]

-3(x + 5) = -9
-3x + -15 = -9
-3x - 15 = -9
-3x - 15 + 15 = -9 + 15 (we added 15 to both sides of the equation because now, the 15 on the left side cancels out).
-3x = 6
-3x/-3 = 6/-3
X = -2
So, in conclusion, X is equal to -2.

5 0

2 years ago

Read 2 more answers

Antonio is going to the carnival. He can spend no more than $20.00. if the ticket to in is $7.50, and each ride cost $1.25, how

fgiga [73]

$20.00 ≥ 7.50+1.25x
subtract 7.50 from both sides
20-7.50=12.50
12.50=1.25x
12.50/1.25=10
x= 10 rides

6 0

3 years ago

WILL MARK BRAINLIEST IF GOTTEN RIGHT IF GOTTEN WRONG ON PURPOSE OR IF YOU DONT KNOW I WILL REPORT YOU :)

ludmilkaskok [199]

Answer:

I'm like 99.8 percent sure it's b5