I need help with number 46.

Mathematics

1 answer:

grigory [225]3 years ago

6 0

Answer:

1:3

Step-by-step explanation:

1/3:1

We want the ratio with whole numbers

Multiply each side by 3

1/3*3 : 1*3

1:3

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The product of 2√ 3 and 3√12 in simplified form is .

borishaifa [10]

Answer:

Step-by-step explanation:

Rewrite this as

(2)(3)(√3)(√12), or

6 * √36, or

6 * 6 = 36

5 0

2 years ago

7.7.33

GenaCL600 [577]

We know that

At sea level, the height is 0 and
the pressure is 98 kilopascals

At 1000 ft, the height is 1000 and
the pressure decreases about 11.41%

i(100%-11.41%)/100----> (0.8859)

therefore
1) at 1000 ft--------> the pressure is 98*(0.8859)----------> 86.82 kilopascals
2) at 2000 ft--------> the pressure is 86.82*(0.8859)-------> 76.91 kilopascals
3) at 3000 ft--------> the pressure is 76.91*(0.8859)-------> 68.14 kilopascals
4) at 4000 ft---------> the pressure is 68.14*(0.8859)-------> 60.36 kilopascals

the answer is
The pressure at an altitude of 4000 m is about 60.36 kilopascals

7 0

3 years ago

Log (5x) (x)= 7/2

vagabundo [1.1K]

Answer:

$x = \frac{\sqrt{70} }{10}, - \frac{\sqrt{70} }{10}$

4 0

2 years ago

Use theorem 7. 4. 2 to evaluate the given laplace transform. do not evaluate the convolution integral before transforming. (writ

irga5000 [103]

With convolution theorem the equation is proved.

According to the statement

we have given that the equation and we have to evaluate with the convolution theorem.

Then for this purpose, we know that the

A convolution integral is an integral that expresses the amount of overlap of one function as it is shifted over another function.

And the given equation is solved with this given integral.

So, According to this theorem the equation becomes the

$\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{ \mathscr{L} (e^{-\tau} \cos \tau ) }{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{\frac{s+1}{(s+1)^2+1}}{s} \\\mathscr{L} \left( \int_{0}^{t} e^{-\tau} \cos \tau d \tau \right) = \frac{1}{s}\left (\frac{s+1}{(s+1)^2+1} \right).$