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3 years ago

WILL GIVE BRAINLIEST AND 20 POINTS! PLEASE SHOW WORK!

Mathematics

1 answer:

kiruha [24]3 years ago

6 0

The number of different 8 digit phone numbers we can have that do not contain the digit 2 is 43046721 numbers

Since there are 10 digits in our number system from 0 to 9, and we are looking for the number of different 8-digit phone numbers that do not contain the digit 2, we would be one digit short. So, for each digit position, we would have 10 - 1 digits = 9 digits.

Since we have 8 places for each digits, for the first place, we have 9 digits. For the second place, we have another 9 digits and so on till we get to the 8 th digit place.

So, for all 8 digit places, we have 9 × 9 × 9 × 9 × 9 × 9 × 9 × 9 × 9 = 9⁸.

So, the number of different 8 digit phone numbers we can have that do not contain the digit 2 is 9⁸ numbers = 43046721 numbers.

Thus, the number of different 8 digit phone numbers we can have that do not contain the digit 2 is 43046721 numbers.

Learn more about multiplication principle of counting here:

brainly.com/question/1091225

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3 years ago

Which value is equivalent to 7 x 5 x 2 divided by 7 x 3 to the 2nd power x 5 to the 0 power divided by 2 to the negative 3rd pow

FinnZ [79.3K]

Answer:

This is hard to read, but i guess that the equation is:

$7*5*2/7*3^2*5^0/2^{-3}*2^{-9}$

So we have some things to solve:

First, for any number:

x^0 = 1

then 5^0 = 1.

And for negative powers,

x^-n = (1/x)^n.

And we

Then we can rewrite our equation as:

$\frac{7*5*2*3^2*1*2^3}{7*2^9}$

now we can cancel the seven in the numerator and the denominator

$\frac{5*2*3*2^3}{2^9}$

now, remember the relation:

a^x*a^y = a^(x+y)

then:

2*2^3 = 2^4

and 2^4/2^9 = 2^-5 = (1^2)^5

Then our equation is:

$\frac{5*3}{2^5}$

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3 years ago

How do you solve this?

posledela

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3 years ago

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Nataly [62]

Answer:

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Step-by-step explanation:

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3 years ago

81x-27=81x−27<br><br> what<br> is the answer

kykrilka [37]

The answer is all real numbers for x

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2 years ago

Read 2 more answers