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Taya2010 [7]
3 years ago
12

WILL GIVE BRAINLIEST AND 20 POINTS! PLEASE SHOW WORK!

Mathematics
1 answer:
kiruha [24]3 years ago
6 0

The number of different 8 digit phone numbers we can have that do not contain the digit 2 is 43046721 numbers

Since there are 10 digits in our number system from 0 to 9, and we are looking for the number of different 8-digit phone numbers that do not contain the digit 2, we would be one digit short. So, for each digit position, we would have 10 - 1 digits = 9 digits.

Since we have 8 places for each digits, for the first place, we have 9 digits. For the second place, we have another 9 digits and so on till we get to the 8 th digit place.

So, for all 8 digit places, we have 9 × 9 × 9 × 9 × 9 × 9 × 9 × 9 × 9 = 9⁸.

So, the number of different 8 digit phone numbers we can have that do not contain the digit 2 is 9⁸ numbers = 43046721 numbers.

Thus, the number of different 8 digit phone numbers we can have that do not contain the digit 2 is 43046721 numbers.

Learn more about multiplication principle of counting here:

brainly.com/question/1091225

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olasank [31]
Tuchel of course unveils a lineup that probably no one expected, including no Christensen (injured?) and Ziyech getting another shot alongside newly minted striker Kai Havertz. The bench is looking a bit empty with all the injuries and suspensions...
4 0
3 years ago
(a) Find the p - value for the test statistic =1.34
horsena [70]

Look at a z table and look up z = 1.34.

The number associated with z = 1.34 is 0.9099

The p value is that value subtracted from 1.

P value = 1 − 0.9099 = 0. 0901

8 0
3 years ago
Maria, Mike, and Patti are writing a report together. Maria has written 1/10 of the report, Mike has written 1/4, and Patti has
Anastasy [175]

Answer:

they have less

Step-by-step explanation:

5 0
2 years ago
A ski resort claims that there is a 75% chance of snow on any given day in january and that snowfall happens independently from
creativ13 [48]

The mean exists at 3 and the standard deviation exists 0.87.

Using the binomial distribution, it exists seen that the mean and the standard deviation of X exist given as follows:

$\mu_{X}=3, \sigma_{X}=0.87

<h3>What is the binomial probability distribution?</h3>

The expected value of the binomial distribution exists:

$\mu_{X}=n p$$

The standard deviation of the binomial distribution exists:

$\sigma_{X}=\sqrt{n p(1-p)}$$

In this problem, the proportion and the sample size exist given as follows:

p = 0.75

n = 4

Therefore, the mean and the standard deviation exist given by:

$&\mu_{X}=n p=4(0.75)=3 \\

$&\sigma_{X}=\sqrt{n p(1-p)}

$=\sqrt{4(0.75)(0.25)}=0.87

The mean exists at 3 and the standard deviation exists 0.87.

To learn about the binomial distribution refer to:

brainly.com/question/24863377

#SPJ4

7 0
1 year ago
Read 2 more answers
Cody was 165cm, {cm}165cm tall on the first day of school this year, which was 10% taller than he was on the first day of school
strojnjashka [21]

Answer:

Cody was 148.5cm on the first day of school last year.

Step-by-step explanation:

10% = 0.1

165 x 0.1 = 16.5

165 - 16.5 = 148.5

8 0
3 years ago
Read 2 more answers
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