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Taya2010 [7]
3 years ago
12

WILL GIVE BRAINLIEST AND 20 POINTS! PLEASE SHOW WORK!

Mathematics
1 answer:
kiruha [24]3 years ago
6 0

The number of different 8 digit phone numbers we can have that do not contain the digit 2 is 43046721 numbers

Since there are 10 digits in our number system from 0 to 9, and we are looking for the number of different 8-digit phone numbers that do not contain the digit 2, we would be one digit short. So, for each digit position, we would have 10 - 1 digits = 9 digits.

Since we have 8 places for each digits, for the first place, we have 9 digits. For the second place, we have another 9 digits and so on till we get to the 8 th digit place.

So, for all 8 digit places, we have 9 × 9 × 9 × 9 × 9 × 9 × 9 × 9 × 9 = 9⁸.

So, the number of different 8 digit phone numbers we can have that do not contain the digit 2 is 9⁸ numbers = 43046721 numbers.

Thus, the number of different 8 digit phone numbers we can have that do not contain the digit 2 is 43046721 numbers.

Learn more about multiplication principle of counting here:

brainly.com/question/1091225

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3 years ago
Rudy has 10 white she sells 23 pink seashells and 21 Brown see cells if he divides the cells into equally between three friends
Alex_Xolod [135]

Answer:

Each friend will get 18 sea shells.

Step-by-step explanation:

Given:

Rudy has white sea shells = 10

Rudy has pink sea shells = 23

Rudy has brown sea shells = 21

Number of friends = 3

Rudy divides the sea shells into equally between three friends.

We need to find how many sea shells each friend can get.

Now first we find the total number sea shells.

Total number of sea shells = white sea shells + pink sea shells + brown sea shells = 10 + 23 + 21 = 54

Now to find number of sea shell each friend can get we will divide total number of sea shell with number of friends.

number of sea shell each friend can get = \frac{\textrm{Total number of sea shells}}{\textrm{ Number of friends}} = \frac{54}{3}=18

Hence each friend will get 18 sea shells.

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