Question

Suppose we are given a square coil that is 5.5 cm on a side containing 100 loops of very fine wire. The total resistance of this coil is 1.7 ✕ 10−3 Ω. This coil is initially centered on the origin with its sides parallel to the x- and y-axes. It is being rotated about the y-axis in a uniform magnetic field of 1.3 T along the z-axis, with an angular velocity of 2.0 rad/sec. Find the magnitude of the peak value of the induced current flowing in this coil under these conditions.

Answer 1

Answer:

I = 578A

Explanation:

The magnitude of the peak value of the induced current flowing in a coild is given by

$I = \frac{\epsilon_{max}}{R}$

$I = \frac{NBA\omega}{R}$

Where

I= current

N = Number of loops

$\omega =$ angular velocity

R= Resistance

B = Magnetic field

A = Area

Replacing our values we have that,

$I = \frac{(100)(1.3)(0.055)^2(2.5)}{1.7*10^{-3}}$

$I = 578A$