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Komok [63]
3 years ago
9

What are the top two gasses in the earth’s atmosphere ?

Physics
1 answer:
ch4aika [34]3 years ago
7 0

Answer:

Nitrogen and oxygen are by far the most common; dry air is composed of about 78% nitrogen (N2) and about 21% oxygen (O2). Argon, carbon dioxide (CO2), and many other gases are also present in much lower amounts; each makes up less than 1% of the atmosphere's mixture of gases.

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A(n) 1100 kg car is parked on a 4◦ incline. The acceleration of gravity is 9.8 m/s 2 . Find the force of friction keeping the ca
igomit [66]

Answer:

Force of friction, f = 751.97 N

Explanation:

it is given that,

Mass of the car, m = 1100 kg

It is parked on a 4° incline. We need to find the force of friction keeping the car from sliding down the incline.

From the attached figure, it is clear that the normal and its weight is acting on the car. f is the force of friction such that it balances the x component of its weight i.e.

f=mg\ sin\theta

f=1100\ kg\times 9.8\ m/s^2\ sin(4)

f = 751.97 N

So, the force of friction on the car is 751.97 N. Hence, this is the required solution.

3 0
3 years ago
What is the slope of the line plotted below?<br> A. 1.33<br> B. -1.33<br> C. -0.6<br> D. 0.6
Naya [18.7K]

Answer:

C. -0.6

Explanation:

Line is passing through the points ( - 3, 1) & (2, - 2)

Slope of line

=  \frac{ - 2 - 1}{2 - ( - 3)}  =  \frac{ - 3}{2 + 3}  =  \frac{ - 3}{5}  =  - 0.6 \\

4 0
4 years ago
Two forces are exerted on an object in the vertical direction: a 20 N force downward and a 10 N force upward. The mass of the ob
VMariaS [17]

Answer:

They are equal.

Explanation:

6 0
3 years ago
An object in static equilibrium has a coefficient of static friction as 0.110. If the normal force acting on the object is 95.0
goblinko [34]

Answer:

A

Explanation:

I just took the test as well

6 0
3 years ago
Read 2 more answers
A rocket sled accelerates from 10 m/s to 40 m/s in 2 seconds. What is the average acceleration of the sled?
Andreas93 [3]

Answer:

15m/s²

Explanation:

Given parameters:

Initial velocity  = 10m/s

Final velocity  = 40m/s

Time taken  = 2s

Unknown:

Average acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time;

 Acceleration  = \frac{Final velocity   -  Initial velocity }{time}  

  Acceleration = \frac{40 - 10}{2}    = 15m/s²

7 0
3 years ago
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