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Mamont248 [21]
2 years ago
8

If you increase the elasticity of a material, what happens to the speed of a mechanical wave going through it?

Physics
1 answer:
Sophie [7]2 years ago
5 0

Answer:

At the molecular level, materials are held together by bonds, which act like springs for small displacements from the equilibrium spacing between neighboring atoms. Push the atoms close, the bond pushes back to keep them apart. Pull them apart, the bond pulls the atoms closer. For those small displacements, it acts like a spring

The speed of the wave will be related to the stiffness of of those springs - you compress the material - how quickly do all of those little springs rebound and push their neighboring atoms away, sending that wave of compression through the material.

Explanation:

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A total of 2.0x 1013 electrons pass a given point in a wire in 15s. what is the current in the wire
timurjin [86]
The current in a wire is defined as the amount of charge that passes a given point of the wire in a given time:
I= \frac{Q}{\Delta t}
where Q is the charge and \Delta t is the time interval.

Since one electron has a charge of q=1.6 \cdot 10^{-19}C, the total charge of 2.0 \cdot 10^{13} electrons is
Q=qN=(1.6 \cdot 10^{-19} C)(2.0 \cdot 10^{13} )=3.2 \cdot 10^{-6} C

And since the time interval is \Delta t=15 s, the current in the wire is
I= \frac{Q}{\Delta t}= \frac{3.2 \cdot 10^{-6} C}{15 s}=2.1 \cdot 10^{-7}A
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2 years ago
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2 years ago
Power=170 watts time=20 seconds
Art [367]
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2 years ago
During normal beating, a heart creates a maximum 3.95-mV potential across 0.305 m of a person’s chest, creating a 0.75-Hz electr
WINSTONCH [101]

Answer:

E = 0.0130 V/m.

Explanation:

The electric field is related to the potential difference as follows:

E = \frac{\Delta V}{d}

<u>Where:</u>

E: is electric field

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d: is the distance of a person's chest = 0.305 m

Then, the electric field is:

E = \frac{\Delta V}{d} = \frac{3.95 \cdot 10^{-3} V}{0.305 m} = 0.0130 V/m

Therefore, the maximum electric field created is 0.0130 V/m.

I hope it helps you!

7 0
2 years ago
An 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.5-T magnetic field. The loop is rotated so that its
nikdorinn [45]

Answer:

The average induced emf in the loop is 0.20 V

Explanation:

Given:

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According to the faraday's law,

Induced emf is given by

    \epsilon = -\frac{\Delta \phi}{\Delta t}

Where \phi = magnetic flux

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Where A = \pi r^{2}

We neglect minus sign because it's shows lenz law

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Therefore, the average induced emf in the loop is 0.20 V

4 0
3 years ago
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