Where is the hole for the following function located?
2 answers:
<em>At x = -3 is located a hole. </em>
<h2>Explanation:</h2>In this problem, we have the following function:
A hole will lie at the x-values that makes the function undefined, that is, when the denominator is zero. In a mathematical language:
From this equation, we get two solutions:
At those x-values the function will have a hole. From the choices:
<em>At x = -3 is located a hole. </em>
<h2>Learn more:</h2>Derivative: brainly.com/question/13419010
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Answer:
x = 3 ±
Step-by-step explanation:
x² - 6x - 4 = 0 ( add 4 to both sides )
x² - 6x = 4
To complete the square
add ( half the coefficient of the x- term)² to both sides
x² + 2(- 3)x + 9 = 4 + 9
(x - 3)² = 13 ( take square root of both sides )
x - 3 = ± ( add 3 to both sides )
x = 3 ±
Part A)
The given equation is:
The radicand or discriminant(d) of the equation will be:
Since the discriminant is equal to 0, the given quadratic equation has only 1 root. In other words we can say the the given equation is a perfect square.
Part B)
The given equation is:
We can solve this expression by factorization. Factors of middle term are to be made in such a way that their product equals the product of first and third term and sum is equal to the middle term i.e. product should be 4x² and sum should be -4x.
So the two such terms are -2x and -2x. Using the factors and simplifying the equation by taking common we get:
The given equation is:
The radicand or discriminant(d) of the equation will be:
Since the discriminant is equal to 0, the given quadratic equation has only 1 root. In other words we can say the the given equation is a perfect square.
Part B)
The given equation is:
We can solve this expression by factorization. Factors of middle term are to be made in such a way that their product equals the product of first and third term and sum is equal to the middle term i.e. product should be 4x² and sum should be -4x.
So the two such terms are -2x and -2x. Using the factors and simplifying the equation by taking common we get: