<em>At x = -3 is located a hole. </em>
<h2>
Explanation:</h2>
In this problem, we have the following function:

A hole will lie at the x-values that makes the function undefined, that is, when the denominator is zero. In a mathematical language:

From this equation, we get two solutions:

At those x-values the function will have a hole. From the choices:
<em>At x = -3 is located a hole. </em>
<h2>Learn more:</h2>
Derivative: brainly.com/question/13419010
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