Where is the hole for the following function located?

Mathematics

2 answers:

Drupady [299]2 years ago

7 0

<em>At x = -3 is located a hole. </em>

<h2>Explanation:</h2>

In this problem, we have the following function:

$f(x)=\frac{x+3}{(x-4)(x+3)}$

A hole will lie at the x-values that makes the function undefined, that is, when the denominator is zero. In a mathematical language:

$(x-4)(x+3)=0$

From this equation, we get two solutions:

$x=4 \\ \\ x=-3$

At those x-values the function will have a hole. From the choices:

<em>At x = -3 is located a hole. </em>

<h2>Learn more:</h2>

Derivative: brainly.com/question/13419010

#LearnWithBrainbly

Helen [10]2 years ago

3 0

Answer:

At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole. At x = -3 is located a hole.

Step-by-step explanation:

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