A section of wall is being framed, A model of the framing
1 answer:
You might be interested in
Given that <span>3 cards are dealt without replacement in a </span><span>standard deck of 52 cards.
Part A:
There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.
Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17
Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.
Therefore, the probability that <span>all three cards are queens is given by
Part B:
Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.
Part C:
Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.
Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17
Part D:
<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.
Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04
Part E:
<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.
Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
Part A:
There are 4 queens in a standard deck of 52 card, thus the probability that the first card is a queen is given by 4 / 52 = 1 / 13.
Since, the first card is not replaced, thus there are 3 queens remaining and 51 ards remaining in total, thus the probability that the second card is a queen is given</span> by 3 / 51 = 1 / 17
Similarly the probability that the third card is a queen is given by 2 / 50 = 1 / 25.
Therefore, the probability that <span>all three cards are queens is given by
Part B:
Yes the probability of drawing a queen of heart is independent of the probability of drawing a queen of diamonds because they are separate cards and drawing one of the cards does not in any way affect the chance of drawing the other card.
Part C:
Given that the first card is a queen, then there are 3 queens remaining out of 51 cards remaining, thus the number of cards that are not queen is 51 - 3 = 48 cards.
Therefore, </span>if the first card is a queen, the probability that the second card will not be a queen is given by 48 / 51 = 16 / 17
Part D:
<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining.
Therefore, </span>if two of the three cards are queens ,<span>the probability that you will be dealt three queens</span> is given by 2 / 50 = 1 / 25 = 0.04
Part E:
<span>Given that the first two card are queens, then there are 2 queens remaining out of 50 cards remaining, thus the number of cards that are not queen is 50 - 2 = 48 cards.
Therefore, </span>if two of the three cards are queens ,the probability that the other card is not a queen is given by 48 / 50 = 24 / 25 = 0.96
Answer:
Brand X has to mix 8.4 oz of brand A mixed nuts which contain 35% peanuts and 12.6 oz of brand B mixed nuts which contain 25%, to obtain 21 oz. Bags of mixed nuts that contain 29% peanuts.
Step-by-step explanation:
Hi
We define
, wich means Brand A has 1 oz containing 35% peanuts.
, wich means Brand b has 1 oz containing 25% peanuts.
So we can build an equiation system
(1)
(2), after fixing it a little
(2)
As we can use any method to solve the system, I used a calculator wich thrown the following results and
.