Answer:
He must earn $2,400 to cover both leisure and $2,160 for school expenses.
Step-by-step explanation:
Let the total amount Ken must earn be k. Then 10% of that would cover leisure activities and the remaining 90% specifically for school expenses.
Then 0.90k = $2,160, and k = $2,400.
He must earn $2,400 to cover both leisure and $2,160 for school expenses.
All fractions that are less than 1/2 but more than 0.
The inequality is 0>1/2
Answer:
-<u>One Equation</u>: is set equal to a variable
Example:
y = 2x + 1
x + 3y = -12
You already have y, plug it back into x + 3y = -12
x + 3(2x + 1) = -12
x + 6x + 3 = -12
7x + 3 = -12
(Subtract 3 from each side)
7x = -15
(Divide by 7)
x = - 2.14
-<u>No Equation</u>: is set equal to a variable
Example:
2x + y = 10
4× + 2y = -3
Subtract 2x from each side of 2x + y = 10, you should get y= -2x + 10. Now that you have found y, substitute y into 4x+ 2y = -3.
4x + 2(-2x + 10) = -3
4x + -4x + 20 = -3
(Subtract 20 from each side)
4x + -4x = -23
(Add 4x and -4x)
0 = -23
No Solution
<u>-Both</u><u> </u><u>Equations</u>: are set equal to a variable
Example:
y = x + 5
y = -x + 3
(you already have y so plug it into the other equation to solve for x)
-x + 3 = x + 5
(Add -x on both sides)
3 = 2x + 5
(subtract 5 from both sides)
-2 = 2x
(Divide by 2 on each side)
x = -1
I hope this helped!
Answer:
3/4 of a 6-ounce glass will be drunk by her in one hour.
Step-by-step explanation:
Given time = 2/3 of hour
= 2/3 (60) As hour = 60 mins
= 120/3
= 40 mins
Given quantity of water = 1/2 of 6-ounce
= 3 ounce
So,
In 40 mins, water intake is 3 ounce
In 1 min, water intake is 3/40
In 60 mins, water in take is (3/40)*60 = 4.5 ounce
Quantity of water intake in 60 mins:
4.5 ounce or 3/4 of 6-ounce glass
I hope it will help you.
