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Andrei [34K]
3 years ago
14

On average, about 240 people visit a local food pantry every day and search up groceries. On an extremely cold day, visitors to

the food pantry can be 175% of an average amount. About how many visitors may go to the food pantry on an extremely cold day?
Mathematics
2 answers:
Charra [1.4K]3 years ago
8 0
The answer is 420 people
solmaris [256]3 years ago
8 0
So basically you just want to multiple 240 by 175%, or 1.75.
240 * 1.75 = 420 (lol hehe)
About 420 visitors may go to the food pantry on an extremely cold day.

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Rectangle
Viefleur [7K]

Answer:

  21 square units

Step-by-step explanation:

The sides of the rectangle are aligned with the coordinate grid, so we can easily find its dimensions.

AB lies on the line y = -2, so the horizontal extent is the difference in x-values:

  6 - 3 = 3

BC lies on the line x = 6, so the vertical extent is the difference in y-values:

  5 -(-2) = 7

The area is the product of these two dimensions:

  A = LW = (7)(3) = 21 . . . . square units

The area of the rectangle is 21 square units.

3 0
3 years ago
Read 2 more answers
GRE Test: The Graduate Record Examination (GRE) is a test required for admission to many US graduate schools. Student’s scores o
Zepler [3.9K]

Answer:

a) \bar X=144.3

b) The 95% confidence interval would be given by (138.846;149.754)      

c) n=34

d) n=298

e) n=1190

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean with this formula:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

\bar X=144.3 represent the sample mean  

\mu population mean (variable of interest)

\sigma=8.8 represent the population standard deviation

n=10 represent the sample size  

a) Find a point estimate of the population mean

We can calculate the sample mean with this formula:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

\bar X=144.3

b) Construct a 95% confidence interval for the true mean score for this population.

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that t_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

144.3-1.96\frac{8.8}{\sqrt{10}}=138.846    

144.3+1.96\frac{8.8}{\sqrt{10}}=149.754

So on this case the 95% confidence interval would be given by (138.846;149.754)    

Part c

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =+20 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got z_{\alpha/2}=1.960, replacing into formula (5) we got:

n=(\frac{1.960(8.8)}{3})^2 =33.05 \approx 34

So the answer for this case would be n=34 rounded up to the nearest integer

Part d

n=(\frac{1.960(8.8)}{1})^2 =297.493 \approx 298

So the answer for this case would be n=298 rounded up to the nearest integer

Part e

n=(\frac{1.960(8.8)}{0.5})^2 =1189.97 \approx 1190

So the answer for this case would be n=1190 rounded up to the nearest integer

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3 years ago
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Likurg_2 [28]
If quadrilateral JKLM has given values, as well as quadrilateral ABCD, it can be concluded from the given values if JKLM is a result of a dilation of ABCD by a scale factor of 2. Dilation factor is used to scale up a given figure. If ABCD has measurements of 1, 2, 3, and 4. Then the measurements of JKLM should be 4, 8, 12, and 16. 
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3 years ago
Write the ratio in two other ways.<br><br> 2 to 3
maw [93]
2/3 
2:3
Hope this helps!
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3 years ago
Evaluate 2p - 99 for p = 7 and g = 6.<br> The value of the expression is
charle [14.2K]

Answer:

(2 \times 7) - (9 \times 6) =  - 40

3 0
3 years ago
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