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Soloha48 [4]
2 years ago
8

Whats 15-b=4b-5(5-3)

Mathematics
1 answer:
Gala2k [10]2 years ago
5 0

15-b=4b-5(5-3)

Multiply the bracket by -5

(-5)(5)=-25

(-5)(-3)=15

15-b=4b-25+15

15-b=4b-10

Move 15 to the other side

Sign changes from +15 to -15

15-15-b=4b-10-15

-b=4b-25

Move 4b to the other side.

-b-4b=4b-4b-25

-b-4b=-25

-5b=-25

divide both sides by -5

-5b/-5=-25/-5

Answer: b=5

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How do you simply -12x=12x into an x='s answer?
dedylja [7]

-12x = 12x

Start by moving all the terms with the variable you want to solve for on one side of the equation and the rest on the other side of the equation.

We will move 12x to the left side of the equation by subtracting 12x from both sides. Now your equation should look like:

-24x = 0

Isolate the variable x by dividing both sides by -24. Everything divided by 0 is equal to 0, so that means x will be equal to 0.

x = 0

Your answer is x = 0.

3 0
3 years ago
Write the denominator of the rational number257/500 in the form 2 m x 5 n , m and n are negative integers Hence write its decima
maw [93]

Answer:

0.514

Step-by-step Explantion:

Denominator = 500 = 2^2 * 5^3

257/500 = 257/2^2*5^3 = 2*257/2*2^2*5^3 = 514/2^3*5^3 = 514/(2*5)^3 = 514/10^3 = 0.514

6 0
3 years ago
If vector v has an initial point at P1 and a terminal point at P2, write v as multiples of the basis vectors That is, write v in
pantera1 [17]

Answer:

v=9i+3j

Step-by-step explanation:

The given vector, v has initial point at P1 = (−5, −2) and terminal point at P2 = (4, 1).

The vector v is found by subtraction the initial point from the terminal point.

v=<4,1>-<-5,-2>

v=<4--5,1--2>

v=<9,3>

We write v as multiples of the basis vectors to obtain:

v=9i+3j

8 0
3 years ago
Line AB contains points A(-6,1) and B(1,4).
Free_Kalibri [48]

To solve this problem you must apply the proccedure shown below:

1- You have that the equation of the line is:

y=mx+b

Where m is the slope andb is the y-intercept.

2- Based on the information given in the problem, the lines AB andCD are parallel, which means that both have the same slope. Therefore, you can calculate the slope of AB:

m=\frac{y2-y1}{x2-x1}

m=\frac{4-1}{1-(-6)}=\frac{3}{7}

3- Use the coordinates of the point D(7,2) to calculate the y-intercept:

2=\frac{3}{7}(7)+b

4. Solve for b:

b=2-3=-1

5. The equation of the line CD is:

y=\frac{3}{7}x-1

The answer is: y=\frac{3}{7}x-1

6 0
3 years ago
What is the slope of the line represented by the equation –5x 2y= 10 ?
Sladkaya [172]
In the equation y=mx+b, the variable m represents the slope of the line. Therefore, the equation -5x+2y=10 can be rearranged into 2y=5x+10. Isolate the y to get y=2.5x+5. The slope of the line is 2.5
7 0
3 years ago
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