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2 years ago

Solve problem to find π (please add steps) A=1/2πr^2

Mathematics

1 answer:

PtichkaEL [24]2 years ago

3 0

Answer:

Π = 2A/r^2

$\pi = \frac{2a}{ {r}^{2} }$

Step-by-step explanation:

Get rid of the half by taking it to the left side or multiplying a fraction by it's denominator to get rid of it. If you multiplying by it's denominator you must also do the same for the other side. Then get rid of the radius by dividing or taking it to the other side, isolating pi.

Hope this helps. :)

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Thanks for the help! Been stuck on this one for a little while.

igor_vitrenko [27]

Answer:

B. $\sqrt{14}$

Step-by-step explanation:

Since 3.74 is rounded to the hundredths place, it is not the ideal exact solution for m^2 = 14.

To solve for m you would have to square root m and 14, which gives you $\sqrt{14}$ . This is the best answer for the problem.

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2 years ago

Factorise 2p^2 - p - 10<br> (2p squared)

velikii [3]

2p² - p - 10 = 0

2 = a

- 1 = b

- 10 = c

To factor, find two numbers that multiply to equal a·c and also that have a sum of b

2p² + 4p - 5p - 10 = 0

2p (p + 2) - 5 (p + 2) = 0

<h3>Answer: ( 2p - 5 ) ( p + 2 ) = 0</h3>

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2 years ago

if the sum of the first 60 positive integers is s, what is the sum of the first 120 integers in terms of s? a. 2s 3600 b. s^2 36

kvasek [131]

For the first 60 positive integers, a = 1, n = 60, l = 60.
Sn = n/2(a + l)
s = 60/2(1 + 60) = 30(61)

For the next 60 positive integer, a = 61, n = 60, l = 120
Sum = 60/2(61 + 120) = 30(61 + 120) = 30(61) + 30(120) = s + 3600

Sum of first 120 positive integers = s + s + 3600 = 2s + 3600

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3 years ago

If y varies jointly as x and z and y = 4 when x = 2 and z = 3, what is y when x = -6 and z = 2?

sp2606 [1]

Answer:

Step-by-step explanation:

Y = kxz

Putting values of y x and z in the equation

4 = k(2)(3)

4 = k6

2/3 = k

Now finding y when x = - 6 and z = 2

Y = kxz

= 2/3(-6)(2)

= - 8

3 0

3 years ago

Why is the square root of 144 rational

Vitek1552 [10]

The square root of 144= 12. 12 is an integer, integers are always rational since they can be written into a fraction.

7 0

2 years ago