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Ksivusya [100]
4 years ago
13

When heat is removed, how does a gas become a liquid?

Physics
2 answers:
White raven [17]4 years ago
8 0
I think the correct answer from the choices listed above is option A. When heat is removed, a gad become a liquid because the  particles in a liquid have less kinetic energy than the particles in gas. As the heat is removed, the particles will experience in decrease of their kinetic energies.
Evgen [1.6K]4 years ago
4 0

Answer:

A.The particles in a liquid have less kinetic energy than the particles in gas

Explanation:

As we know that the kinetic energy of the gas is directly depends on the temperature of the gas

It is given by the formula

U = \frac{3}{2}nRT

since the heat is removed from the gas then due to removal of energy the temperature of the gas molecules will decrease.

Due to this decrease in energy the molecules of gas will come closer and the force between the molecules will increase.

Now due to stronger attraction force the gas will convert into liquid

so correct answer will be

A.The particles in a liquid have less kinetic energy than the particles in gas

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A solid block of mass m is suspended in a liquid by a thread. The density of the block is greater than that of the liquid. Initi
Tanzania [10]

Answer:

(C) T

The tension T at equilibrium will be equal to the Buoyant force.

The Buoyant force is given by:

Fb = density x acceleration due to gravity x volume displaced

The change in height doesn't affect the Buoyant force and hence the tension.

Note: The figure of question is added in the attachment

3 0
3 years ago
When the two surfaces of a thin film are parallel and the light is incident at some angle what fringes are formed? A. Circular B
lord [1]

Answer:

The correct option is;

A. Circular

Explanation:

Some of the light that impinges on the surface are reflected and the rest are transmitted to a different medium

At the surface of the next medium also, some of the light are transmitted while the others are reflected and refracted through the first medium

The speed of light (and hence the wavelength and color) refracted through the thin film is changed as the distance the refracted light travels through the thin film is increased as we move away from the point directly in the front view to some distance as the reflected light path from those distance to the eye is increased due to their inclination giving them a different wavelength which are all equal at a radial distance from the eye hence forming a circular fringes.

8 0
3 years ago
I need help on edge
maks197457 [2]
It is wave front
That’s the answer
8 0
3 years ago
Wall-E the robot is resting when he randomly explodes into two pieces that fly off in opposite directions. His head has a mass o
Brut [27]

Answer:

<em>The body flies off to the left at 9.1 m/s</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum </u>

It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is  

P=mv.  

If we have a system of bodies, then the total momentum is the sum of the individual momentums:

P=m_1v_1+m_2v_2+...+m_nv_n

If a collision occurs and the velocities change to v', the final momentum is:

P'=m_1v'_1+m_2v'_2+...+m_nv'_n

Since the total momentum is conserved, then:

P = P'

In a system of two masses, the equation simplifies to:

m_1v_1+m_2v_2=m_1v'_1+m_2v'_2\qquad\qquad[1]

Wall-E robot is initially at rest, its two parts together. His head has a mass of m1=0.75 kg and his body has a mass of m2=6.2 kg. Both parts have initial speeds of zero v1=v2=0.

After the explosion, his head flies off to the right at v1'=75 m/s. We are required to find the speed of his body v2'. Solving [1] for v2':

\displaystyle v'_2=\frac{m_1v_1+m_2v_2-m_1v'_1}{m_2}

Substituting values:

\displaystyle v'_2=\frac{0.75*0+6.2*0-0.75*75}{6.2}

\displaystyle v'_2=-9.1 \ m/s

The body flies off to the left at 9.1 m/s

3 0
3 years ago
Find the magnitude of the impulse delivered to a soccer ball when a player kicks it with a force of 1450 N . Assume that the pla
juin [17]

To solve this problem we will apply the concept of Impulse. Which is described as the product between the Force and the change in time. Mathematically this can be described as

I = F \Delta t

Where,

F = Force

\Delta t= Time

Our values are given as,

F = 1450N

\Delta t = 5.1*10^{-3} s

Replacing we have,

I = (1450)(5.1*10^{-3})

I = 7.395Kg\cdot m/s

Therefore the impulse delivered to the soccer ball is 7.395Kg\cdot m/s or  7.395N\cdot s

4 0
3 years ago
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