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3 years ago

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You have just moved into a new apartment and are trying to arrange your bedroom. You would like to move your dresser of weight 3

,500 N across the carpet to a spot 5 m away on the opposite wall. Hoping to just slide your dresser easily across the floor, you do not empty your clothes out of the drawers before trying to move it. You push with all your might but cannot move the dresser before becoming completely exhausted. How much work do you do on the dresser?
W> 1.75 x 10^4 J
W = 1.75 x 10^4 J
1.75 x 10^4 J > W > 0 J
W = 0 J

1 answer:

Mazyrski [523]3 years ago

8 0

Answer:

0.

Explanation:

(A) Work done on the dresser which will be given as :

$W = F d cos \theta$

where, F = weight of the dresser = 3500 N

$d_{expected} = 5m$

However you can move the dresser, that is a real distance,

$d = 0 m$

Substituting,

$W = (0) F(3500)cos (\theta)$ ( $\theta$ is the angle at which you apply the force)

$W = 0 J$

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2 years ago

The time T in seconds for a pendulum of length L feet to make one swing is given by Upper T=2\pi \sqrt((L)/(36)). How long is a

Andreyy89

Answer:

3.6ft

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To solve for L, first move 2*n over:

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(T/(2*π))2 = L/32

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3 years ago

The force exerted by the wind on the sails of a sailboat is Fsail = 330 N north. The water exerts a force of Fkeel = 210 N east.

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Answer:

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Explanation:

From the question we are told that

The force exerted by the wind is $F_{sail} = (330 ) \ N \ north$

The force exerted by water is $F_{keel} = (210 ) \ N \ east$

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Now the acceleration towards the north is mathematically represented as

$a_n = \frac{F_{sail}}{m_b}$

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$a_e = \frac{F_{keel}}{m_b }$

substituting values

$a_e = \frac{210}{260}$

$a_e =0.808 \ m/s^2$

The resultant acceleration is

$a_r = \sqrt{a_e^2 + a_n^2}$

substituting values

$a_r = \sqrt{(0.808)^2 + (1.269)^2}$

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The direction with reference from the north is evaluated as

Apply SOHCAHTOA

$tan \theta = \frac{a_e}{a_n}$

$\theta = tan ^{-1} [\frac{a_e}{a_n } ]$

substituting values

$\theta = tan ^{-1} [\frac{0.808}{1.269 } ]$

$\theta = tan ^{-1} [0.636 ]$

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