Orbits are the result of a perfect balance between the forward motion of a body in space, such as a planet or moon, and the pull of gravity on it from another body in space, such as a large planet or star. An object with a lot of mass goes forward and wants to keep going forward; however, the gravity of another body in space pulls it in. There is a continuous tug-of-war between the one object wanting to go forward and away and the other wanting to pull it in.

8 0

3 years ago

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A steel ball with mass m=5.21 g is moving horizontally with speed ????=412 m/s when it strikes a block of hardened steel with ma

docker41 [41]

Answer:

a) The speed of the block immediately after the collision is $v_{2f}=(0.289\±0.002)m/s$ .

b) The impulse exerted on the block is $p_{2}=(4.2772\±0.0296)kg*m/s$ .

Explanation:

a) As this is a perfectly elastic collision, we can use the formula $v_{2f}=(\frac{2m_{1} }{m_{1}+m_{2}} ) v_{1i}+ (\frac{m_{2}-m_{1}}{m_{1}+m_{2}} )v_{2i}$ , due $v_{2i}=0m/s$ , we obtain $v_{2f}=(\frac{2m_{1} }{m_{1}+m_{2}} ) v_{1i}$ . Then with the data that we know $m_{1}=5.21g=0.00521kg, m_{2}=14.8kg$ and $v_{1i}=412m/s$ , therefore $v_{2f}=(\frac{2(0.00521kg) }{0.00521kg+14.8kg} ) 412m/s=0.289m/s$ or $v_{2f}=(0.289\±0.002)m/s$ adding uncertainty.

b) Now that we know the speed we can use $p_{2}=m_{2}*v_{f2} =14.8kg*(0.289\±0.002)m/s=(4.2772\±0.0296)kg*m/s.$

8 0

4 years ago

A 150 g baseball pitched at a speed of 45 m/s is hit straight back to the pitcher at a speed of 60 m/s. What is the magnitude of

abruzzese [7]

Answer:

The average force is 1578.94 N.

Explanation:

Given that,

Mass of baseball = 150 g

Speed = 45 m/s

Speed of pitcher = 60 m/s

Time = 9.5 ms

We need to calculate the average force

Using formula of impulse

$J=\Delta p$

$J=m\Delta v$ ...(I)

$J=F\Delta t$ ....(II)

From equation (I) and (II)

$F=\dfrac{m(v_{f}-v_{i})}{\Delta t}$

Where, m = mass of baseball

$v_{f}$ = final velocity

$v_{i}$ = Initial velocity

$\Delta t$ = time

Put the value into the formula

$F=\dfrac{150\times10^{-3}\times(60-(-40))}{9.5\times10^{-3}}$

$F=1578.94\ N$

Hence, The average force is 1578.94 N.

3 0

4 years ago

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If some electrons are transferred from object A to object B,

Igoryamba

Answer: A. Object A will have a positive charge.

Explanation: If the number of protons and electrons are the same, their net charges cancel each other out, and you have a neutral charge. If electrons are transferred to another object, the amount of positive charge will outweigh the amount of negative charge. As a result, you are left with an overall positive charge in object A. Meanwhile, object B is now negative.

6 0

3 years ago