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uysha [10]
3 years ago
12

A football player runs directly down the field for 45m before turning to the right at an angle of 25 degrees from his original d

irection and running additional 20m before getting tackled. What is the magnitude and direction of the runner's total displacement?​
Physics
1 answer:
Fiesta28 [93]3 years ago
5 0

............................................................................... Hello wonderful person <3

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A flashlight is held at the edge of a swimming pool at a height h = 1.6 m such that its beam makes an angle of θ = 38 degrees wi
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Which body is in equilibrium?
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6 0
3 years ago
Read 2 more answers
A projectile is shot at an angle 45 degrees to the horizontalnear the surface of the earth but in the absence of air resistance.
ivann1987 [24]

Answer:

v₂ = 176.24 m/s

Explanation:

given,

angle of projectile = 45°

speed = v₁ = 150 m/s

for second trail

speed = v₂ = ?

angle of projectile = 37°

maximum height attained formula,

H_{max}= \dfrac{v^2 sin^2(\theta)}{g}

now,

H_{max}= \dfrac{v_1^2 sin^2(\theta_1)}{g}

H_{max}= \dfrac{v_2^2 sin^2(\theta_2)}{g}

now, equating both the equations

\dfrac{v_2^2}{v_1^2}=\dfrac{sin^2(\theta_1)}{sin^2(\theta_2)}

\dfrac{v_2^2}{150^2}=\dfrac{sin^2(45^0)}{sin^2(37^0)}

   v₂² = 31061.79

   v₂ = 176.24 m/s

velocity of projectile would be equal to v₂ = 176.24 m/s

8 0
3 years ago
Choose all the answers that apply.
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Answer:

B and C?

Explanation:

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3 years ago
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