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Ray Of Light [21]
3 years ago
8

A ball with an initial velocity of 25 m/s is subject to an acceleration of -9.8m/s^2 how high does it go before coming to a mome

ntary stop ?

Physics
1 answer:
qwelly [4]3 years ago
8 0

Answer:

The ball will reach an height of 31.88 meters before coming to a stop.

Explanation:

we know that by equation of motion v^{2} = u^{2} + 2as

where v is the final velocity of the ball , u is the initial velocity of the ball , a is acceleration due to gravity and s is the distance traveled by the ball.

a = -9.8 \frac{m}{s^{2}}

and u = 25 m/s

and v = 0

therefore s = \frac{u^{2}}{2a}

so s = 31.88 meters

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