Answer:
The ball will reach an height of 31.88 meters before coming to a stop.
Explanation:
we know that by equation of motion
where v is the final velocity of the ball , u is the initial velocity of the ball , a is acceleration due to gravity and s is the distance traveled by the ball.
a = -9.8
and u = 25 m/s
and v = 0
therefore s =
so s = 31.88 meters
Answer:
0.03605 V/m is the electric field in the gold wire.
Explanation:
Resistivity of the gold =
Length of the gold wire = L = 14 cm = 0.14 m ( 1 cm = 0.01 m)
Diameter of the wire = d = 0.9 mm
Radius of the wire = r = 0.5 d = 0.5 × 0.9 mm = 0.45 mm =
( 1mm = 0.001 m)
Area of the cross-section =
Resistance of the wire = R
Current in the gold wire = 940 mA = 0.940 A ( 1 mA = 0.001 A)
( Ohm's law)
We know, Electric field is given by :
0.03605 V/m is the electric field in the gold wire.
The position vector of the bullet has components
The bullet hits the ground when , which corresponds to time
:
The bullet travels 168 m horizontally, which would require a muzzle velocity such that