Answer:
Explanation:
let the velocity of throw is u .
Time to reach horizontally .25 m is equal to reach .45 m vertically
t = .25 / u cos63
= .55 / u
For vertical motion
- h = - ut + 1/2 gt²
-.45 = -usin63 x .55 / u + .5 x9.8 (.55 / u )²
-.45 = - .49 + 1.48 / u²
.04 = 1.48 / u²
u² = 37
u = 6.08 m /s
Answer:
The man's velocity relative to the moving walkway is, v₂₃ = 0.2 m/s
Explanation:
Given data,
The speed of the moving walkway, v₁₂ = 0.9 m/s
The speed of the man walking on a walkway to the stationary observer, v₁₃ = 1.1 m/s
The speed of the man walking on a walkway to the walkway, v₂₃ = ?
The formula for relative velocity is,
<em> v₁₃ = v₁₂ + v₂₃</em>
∴ v₂₃ = v₁₃ - v₁₂
Substituting the values,
v₂₃ = 1.1 - 0.9
= 0.2 m/s
Hence, the man's velocity relative to the moving walkway is, v₂₃ = 0.2 m/s
Answer:
10 kg
Explanation:
The mass of an object does not change even if the amount of gravtiy changes.
Answer:
No
Explanation:
Acceleration = Velocity/Time
An example of where the velocity would be different is:
Acceleration = (automobile 1)
Acceleration = (automobile 2)
As you can see, the velocity for the first automobile is 10 m/s while the second one has a velocity of 25 m/s (with a greater time travelled) and both resulted in the same acceleration of 5 m/s².
The emf induced = B*l*v where B is the flux density, l the length of the conductor and v the velocity of the conductor. In the given case B = 0.035 N/amp.meter, l = 0.86 and v = 6 m/sec
emf = 0.035*0.86*6 = 0.1806 v ≈ 0.18 v
choice: D