Question

How do you solve these problems?

Answer 1

Answer:

Step-by-step explanation:

Hello,

a. The area of region P is the area of the rectangle 1 * e minus the

$\displaystyle \int\limits^0_1 {e^x} \, dx=[e^x]^{1}_{0}=e-1$

So this is e - (e-1) = e - e + 1 = 1

b. The area of region P is the area of the rectangle 1 * e minus P and minus the

$\displaystyle \int\limits^0_1 {e^{-x}} \, dx=[-e^{-x}]^{1}_{0}=-e^{-1}+1$

So this is

$e - 1 - (-e^{-1}+1) = e-1+e^{-1}-1=e+e^{-1}-2$

This is around 1.08616127...

Hope this helps.

Do not hesitate if you need further explanation.

Thank you