Solve by solution x+4y=4 and 2x-3y=8

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

3 0

I hope this helps you

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Solve for qqq. 3\left(q+\dfrac43\right) = 23(q+ 3 4 )=2<br>pls answer this

enyata [817]

Answer:

Step-by-step explanation:

Given the expression $3\left(q+\dfrac43\right) = 23$ , we are to find the value of q;

$3\left(q+\dfrac43\right) = 23\\on\ expansion\\\\3q + 4/3(3) = 23\\\\3q+4 = 23\\\\subtract \ 4\ from \ both\ sides \ of \ the \ equation\\\\3q+4-4 = 23-4\\\\3q = 19\\\\Diviide \both\ sides \ by \ 3\\\\3q/3 = 19/3\\\\q = 19/3$

Hence the value of q is 19/3

6 0

3 years ago

A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the prob

UkoKoshka [18]

Answer:

The probability that 8 mice are required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates mice, one at a time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

$P(X=r)=^nC_r p^rq^{n-r}$