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Shkiper50 [21]
3 years ago
6

Find the missing side of triangle 8,6

Mathematics
2 answers:
vichka [17]3 years ago
6 0

Answer:

10 (if it is a right triangle)

Step-by-step explanation:

it is a variation of special right triangle 3,4,5

for other right triangle use the equation:

a^{2} +b^{2} =c^{2}

c is the length of the hyponuse and a&b is the length for the 2 other sides.

it only work for right triangles.

Juli2301 [7.4K]3 years ago
3 0

Answer:

10

Step-by-step explanation:

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Order the values least to greatest
Paul [167]

Answer:

9.013, 9.13, 9.1342, 9.2

8 0
3 years ago
If a triangle has side lengths 7, 10, and 12, is it a right triangle??
Vesnalui [34]

Answer:

No. Remember, a right angle must have a 90 degree angle. We can find the lengths with the Pythagorean Theorem.

Step-by-step explanation:

Given the length 7, 10, and 12, we can assume that 12 is the hypotenuse (it is the longest length).

- we can use 7 and 10 interchangeably.

Fill in the equation, a^2 + b^2 = c^2

                 where c = 12, and a or b = 7 or 10.

To indicate if the given lengths would form a right angle, we can only input 7 or 10, not both.

Therefore, 7^2 + b^2 = 12^2 or 10^2 + b^2 = 12^2

7^2 + b^2 = 12^2 ==> 49 + b^2 = 144 ==> <u>b= </u>\sqrt{95<u> ==> </u><u>9.746</u>

b= 9.7, not 10.

10^2 + b^2 = 12^2 ==> 100 + b^2 = 144 ==> <u>b = </u>\sqrt{44<u> ==> </u><u>6.633 </u>

b= 6.6, not 7.

Therefore, the lengths 7, 10, and 12, does NOT make a right triangle.

Hope this helps!

5 0
3 years ago
I NEED HELP!!! ASAP!
iren2701 [21]
I think the correct answer is B.
7 0
3 years ago
A box of cereal states that there are 93 calories in a three fourths
cupoosta [38]

93/3 = 31, 31 x 4= 124

Calories per cup is 124

There are 372 calories in three cups

7 0
3 years ago
Consider the sets below. u = {x | x is a real number} a = {x | x is an odd integer} r = {x | x = 3, 7, 11, 27} is r ⊂ a?
-BARSIC- [3]

The correct option is (B) yes because all the elements of set R are in set A.

<h3>What is an element?</h3>
  • In mathematics, an element (or member) of a set is any of the distinct things that belong to that set.

Given sets:

  1. U = {x | x is a real number}
  2. A = {x | x is an odd integer}
  3. R = {x | x = 3, 7, 11, 27}

So,

  • A = 1, 3, 5, 7, 9, 11... are the elements of set A.
  • R ⊂ A can be understood as R being a subset of A, i.e. all of R's elements can be found in A.
  • Because all of the elements of R are odd integers and can be found in A, R ⊂ A is TRUE.

Therefore, the correct option is (B) yes because all the elements of set R are in set A.

Know more about sets here:

brainly.com/question/2166579

#SPJ4

The complete question is given below:
Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A?

(A) yes, because all the elements of set A are in set R

(B) yes, because all the elements of set R are in set A

(C) no because each element in set A is not represented in set R

(D) no, because each element in set R is not represented in set A

8 0
1 year ago
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