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3 years ago

Name two physical properties that could not be used to distinguish between water and ethanol

1 answer:

8 0

When approaching this question, we need to consider what ethanol and water have in common. The only similarities between the two that come to my mind are the fact that they’re both clear. And they’re both liquids at room temperature.

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What is the VSEPR model of CB4I?

sesenic [268]

Answer:

Molecular geometry Vsepr

According to VSEPR, the valence electron pairs surrounding an atom mutually repel each other; they adopt an arrangement that minimizes this repulsion, thus determining the molecular geometry. This means that the bonding (and non-bonding) electrons will repel each other as far away as geometrically possible.

Explanation:

3 0

4 years ago

Write a balanced chemical equation for the standard formation reaction of solid sodium hydrogen carbonate Write a balanced chemi

4vir4ik [10]

Answer:

Na(s) + C(s, graphite) + 1/2 H₂(g) + 3/2 O₂(g) → NaHCO₃(s)

Explanation:

The standard formation reaction is the synthesis of 1 mole of a substance from its elements in their most stables forms under standard conditions. The balanced chemical equation is:

Na(s) + C(s, graphite) + 1/2 H₂(g) + 3/2 O₂(g) → NaHCO₃(s)

8 0

4 years ago

What are the benefits of taxes? What is the relationship between taxes and the government?

marin [14]

collect this money and use it to finance social projects

__________________________________________

3 0

3 years ago

Read 2 more answers

A 60 and N net force is applied to a 12 kg box which is the acceleration of the box?

GarryVolchara [31]

The relation between force and mass and acceleration is

$Force = mass X acceleration$

The SI unit will be

Force = Newton

mass =kg

acceleration= $\frac{m}{s^{2} }$

thus

$acceleration = \frac{Force}{mass}$

putting values

$acceleration=\frac{60 N}{12kg}=5\frac{m}{s^{2} }$

Thus the acceleration will be

$5\frac{m}{s^{2} }$

6 0

4 years ago

Does anyone know how to do this? the solubility of barium carbonate, BaCO3, is 0.0100 g/L. Its molar mass is 197.3 g/mol. What i

g100num [7]

It's simple, just follow my steps.

1º - in 1 L we have $0.0100~g$ of $BaCO_3$

2º - let's find the number of moles.

$\eta=\frac{m}{MM}$

$\eta=\frac{0.0100}{197.3}$

$\boxed{\boxed{\eta=5.07\times10^{-5}~mol}}$

3º - The concentration will be

$C=5.07\times10^{-5}~mol/L$

But we have this reaction

$BaCO_3\rightleftharpoons Ba^{2+}+CO_3^{2-}$

This concentration will be the concentration of $Ba^{2+}~~and~~CO_3^{2-}$

$K_{sp}=\frac{[Ba^{2+}][CO_3^{2-}]}{[BaCO_3]}$

considering $[BaCO_3]=1~mol/L$

$K_{sp}=[Ba^{2+}][CO_3^{2-}]$

and

$[Ba^{2+}]=[CO_3^{2-}]=5.07\times10^{-5}~mol/L$

We can replace it

$K_{sp}=(5.07\times10^{-5})*(5.07\times10^{-5})$

$K_{sp}\approx25.70\times10^{-10}$

Therefore the $K_{sp}$ is:

$\boxed{\boxed{\boxed{K_{sp}\approx2.57\times10^{-11}}}}$

4 0

4 years ago

Read 2 more answers