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kolezko [41]
3 years ago
5

How many moles are equal to 145 g of sodium carbonate?

Chemistry
2 answers:
vladimir1956 [14]3 years ago
5 0
More explain??!!?!???
slavikrds [6]3 years ago
3 0

Answer:

There are

0.0642 mol Na

2

CO

3

in

6.80 g

.

Explanation:

The chemical formula of sodium carbonate is

Na

2

CO

3

. The molar mass of sodium carbonate is

105.988439 g/mol

.

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qaws [65]

Find your answer in the explanation below.

Explanation:

PV = nRT is called the ideal gas equation and its a combination of 3 laws; Charles' law, Boyle's law and Avogadro's law.

According to Boyle's law, at constant temperature, the volume of a gas is inversely proportional to the pressure. i.e V = 1/P

From, Charles' law, we have that volume is directly proportional to the absolute temperature of the gas at constant pressure. i.e V = T

Avogadro's law finally states that equal volume of all gases at the same temperature and pressure contain the same number of molecules. i.e V = n

Combining the 3 Laws together i.e equating volume in all 3 laws, we have

V = nT/P,

V = constant nT/P

(constant = general gas constant = R)

V = RnT/P

by bringing P to the LHS, we have,

PV = nRT.

Q.E.D

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3 years ago
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3 years ago
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6 0
3 years ago
HELP ASAP!!!
Paraphin [41]
Solution..
---------------

Let's calculate the mass of CO₂.

We have (12+(16*2))
= 12+32
=44gmol¯¹..

a. What is the percent by mass of carbon?

Mass of carbon /mass of CO₂ × 100%

12/44 × 100%

=27.3%...

b. What is the percent by mass of oxygen?

Mass of oxygen/mass of CO₂ × 100%

(2×16)/44 × 100%

32/44 × 100%

=72.7%....

To check.. You'll add this two percentage compositions together and see of it gives 100%... If it does then we're good...

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8 0
4 years ago
Read 2 more answers
Na2SO4 is dissolved in water to make 450mL of a 0.2250 M solution. What is the molar mass of Na2SO4?
Alisiya [41]

Answer:

mass Na2SO4 = 14.3816 g

Explanation:

sln Na2SO4:

∴ V = 450 mL

∴ <em>C </em>=<em> </em>0.2250 mol/L

∴ Mw ≡ 142.04 g/mol.....  from literature

⇒ mol Na2SO4 = (0.2250 mol/L)(0.450 L) = 0.10125 mol

⇒ mass Na2SO4 = (0.10125 mol)(142.04 g/mol) = 14.3816 g

3 0
3 years ago
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